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Leviafan [203]
1 year ago
10

Every $4,000 spent on cable TV will reach 160 fans while every $2,750 spent on radio ad will reach 125 fans. A stadium has estab

lished a goal of reaching 200,000 fans with it's advertisement. It has an advertising budget of $3 million. Which advertising option should the stadium use to meet the goal?
Mathematics
1 answer:
laila [671]1 year ago
8 0

Answer:

Neither of the two advertising options meet the goal.

Step-by-step explanation:

Every $4,000 spent on cable TV will reach 160 fans.

Therefore, the goal of reaching 200000 fans will be fulfilled by \frac{4000 \times 200000}{160} = 5000000 dollars i.e. $5 million which is greater than the budget of $3 million.

Now, every $2,750 spent on radio ads will reach 125 fans.

Therefore, the goal of reaching 200000 fans will be fulfilled by \frac{2750 \times 200000}{125} = 4500000 dollars i.e. $4.5 million which is again greater than the budget of $3 million.

Therefore, neither of the two advertising options meet the goal. (Answer)

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Length: 21 meters

Width: 5.25 meters

<u>Scale changes to 1 cm : 9 cm</u>

- Length: 63 meters

- Width: 15.75 meters

New length is 3 times old length

4 0
2 years ago
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Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, as shown colon
Nadusha1986 [10]

Answer:

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}  where a\geqslant 0"

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Step-by-step explanation:

Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, "

It can be written as \sqrt{54a^7b^3} where a\geqslant 0

The given expression is \sqrt{54a^7b^3} where a\geqslant 0

To find Sadie's error and explain the correct answer :

Sadie's steps are

\sqrt{54a^7b^3}  where a\geqslant 0

=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}

=3ab\sqrt{6a^5b}

<h3>\sqrt{54a^7b^3}=3ab\sqrt{6a^5b} where a\geqslant 0</h3><h3><u>Now corrected steps are</u></h3>

\sqrt{54a^7b^3}  where a≥0

=\sqrt{(9\times 6)(a^{6+1})(b^{2+1})

=\sqrt{(3^2\times 6)(a^6.a^1)(b^2.b^1) (by using the identity a^{m+n}=a^m.a^n

=\sqrt{3^2\times 6\times ((a^3)^2.a)(b^2.b) (by using the identity a^{mn}=(a^m)^n )

=3ab\sqrt{6ab}

Therefore \sqrt{54a^7b^3}=3ab\sqrt{6ab}  where a\geqslant 0

<h3>The correct answer is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b} " where a\geqslant 0

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>
5 0
1 year ago
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Lisa has $150 at most to spend on clothes. She wants to buy a pair of jeans for $58 and will spend the rest on t-shirts that cos
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Answer:

14t + 58 ≤ 150

Step-by-step explanation:

If she cannot spend more than what she has, which is 150, the inequality sign has to be "less than or equal to".  It's ok if she spends less than 150, but not ok if she spends more, because she doesn't have it to spend.

We know the cost of 1 pair of jeans is 58.  Now she wants to make up the difference by getting as many $14 shirts as possible (the number of shirts being our unknown).  

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4 0
2 years ago
HURRY!
kirza4 [7]
Answer: $2.26
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Step-by-step explanation:

Will bought several books that cost $ 2.50 each and received a $ 2 discount on the total bill. If he paid $ 10.50, how many books did he buy ?

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x = 5....he bought 5 books

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2 years ago
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