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ch4aika [34]
2 years ago
15

Freddie put an empty bucket underneath a leaking pipe. After 3/4 hours, Freddie collected 1/2 cups of water. What is the rate, i

n cups per hour, at which the water is leaking from the pipe?
Mathematics
1 answer:
lidiya [134]2 years ago
5 0
0.35 cups/hour

To be able to determine the rate at which the water is leaking from the pipe with the information given, you have to divide the number of cups by the number of hours in which they were collected:
12 cups/34 hours= 0.35 cups/hour
According to this, the answer is that the rate at which the water is leaking from the pipe is 0.35 cups/hour.

Hope this helps!!
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In 1998 the average income for middle class families in the US was $37,100 with a population standard deviation of $6362. We wan
sammy [17]

Answer:

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

The best answer would be:

A. Z test

Step-by-step explanation:

Data given and notation  

\bar X=36670 represent the mean average

\sigma=6362 represent the population standard deviation for the sample  

n=1225 sample size  

\mu_o =37100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 37100, the system of hypothesis would be:  

Null hypothesis:\mu =37100  

Alternative hypothesis:\mu \neq 37100  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

The best answer would be:

A. Z test

5 0
2 years ago
What is the value of n in the equation –negative StartFraction one-half EndFraction left-parenthesis 2 n plus 4 right-parenthesi
fgiga [73]

Answer:

Solution to equation: n = 1

Step-by-step explanation:

We are given the following equation:

-\dfrac{1}{2}(2n + 4) + 6 = -9 + 4(2n + 1)

We have to solve the equation to find the value of n.

Solving the equation, we get,

-\dfrac{1}{2}(2n + 4) + 6 = -9 + 4(2n + 1)\\\\-\dfrac{1}{2}(2n + 4)-4(2n+1) = -9-6\\\\-n-2-8n-4 = -15\\\Rightarrow -9n = -15 + 6\\\Rightarrow -9n = -9\\\Rightarrow n = 1

Thus, value of n is 1.

4 0
2 years ago
Why did the paper rip when the student tried to stretch out the horizontal axis of his graph? Unscramble this letters to figure
Fynjy0 [20]
Tension seems the obvious answer here, but then we are left with x. Since the horisontal line on a graph is 'x'. The answer appears to be Tension X (Tension on X axis. Hope this helps.
8 0
2 years ago
Read 2 more answers
Find all explicit solutions y = ϕ(x) of the DE in part (a) defined by this relation. Give the interval I of definition of each e
Evgen [1.6K]

Answer and Step-by-step explanation:

Firstly, by definition, an interval of definition of any solution is the open interval on which it is defined.

Consider the problem p′=p², p(0)=1, has solution p(t) = 1/(1−t).

The definition of this solution is on the interval (−1/2,1/3), making it an interval of definition of solution.

However, it isn't the largest. The largest interval of definition is (−∞,1).

Consider another problem: p(t)=t√ satisfies the ODE p′=1/(2p).

Meanwhile, when considered as the solution of the ODE above, the domain of square root is [0,∞), and the interval of definition is (0,∞).

But at t=0 the ODE makes no sense, so it would be wrong to assume that y satisfies the ODE in this case. Meanwhile, ODEs are generally considered only on open intervals.

7 0
2 years ago
Kevin, while calculating his tax adjustments, notes that he can make adjustments of $3,435 for contributions to his retirement p
Elina [12.6K]

Gross income is <span>An individual's total personal </span>income<span>, before accounting for taxes or deductions. so the adjusted gross income can be calculated using</span>

AGI = GI – D

Where AGI is the adjusted gross income

GI is the gross income

D are the deductions

AGI = 45942 – ( 3435 + 3393 + 1128 )

<span>AGI = $ 37,896  </span>

6 0
2 years ago
Read 2 more answers
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