Answer:
Since the length of the drawing is 200 ft. and equivalent to 13.33 in. with a scale of 15 ft to 1 in. and the length of the paper is 11 in., Adoncia's drawing will not fit on the sheet of paper
Step-by-step explanation:
The given parameters are;
The scale of the drawing is 15 ft = 1 in.
The actual dimensions of the monument;
Height = 80 ft.
Length = 200 ft.
Therefore, we have;
The required dimension of the paper height = 80/15 = 16/3 = 5.33 in.
The required dimension of the paper length = 200/15 = 40/3 = 13.33 in.
The given paper dimension by 11 in. which is of a dimension of that of a standard letter paper size of 8.5 in. by 11 in.
Drawing length, 13.33 in. > Paper length > 11 in.
Adoncia's drawing will not fit on the sheet of paper.
X = days rented and y = miles driven
4 days rented and 300 miles driven
35x + .375y = total cost
35(4) + .375(300)
140 + 112.5
Total cost = $252.50
F(x) = 6x² + 5 - 42x
first step in writing the f(x) in vertex form? WRITE THE FUNCTION IN STANDARD FORM.
f(x) = 6x² - 42x + 5
Exponents must be in decreasing order.
The total number of both men and women surveyed was 305+279+152+459= 1195. Of this total, 279 women cooked dinner so 279/1195=0.23. This would compare with men which would be 305/1195=0.26 or slightly higher probability.
