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1 year ago

Which triangle defined by three points on the coordinate plane is congruent with the triangle illustrated, and why?

2 answers:

4 0

The triangle defined by three points on the coordinate plane is congruent with the triangle illustrated:

C) (4,2); (8,2); (4,8) because the corresponding pairs of sides and corresponding pairs of angles are congruent.

If we plot these points we can observe that they are congruent, we should also solve for the distance of each point between each other to conclude their congruency.

Harlamova29_29 [7]1 year ago

3 0

The correct answer is D..........

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Amira sells balloon animals. She uses the same number of balloons for each animal she makes. The table compares the number of ba

Vikki [24]

Answer:

4 balloons for each balloon animal.

Step-by-step explanation:

Amira sells balloon animals. The given table compares the number of balloon animals sold and the remaining number of balloons on a certain day.

Animals Balloons

15 200

24 164

33 128

When she sold 15 animals the leftover balloons were 200.

then she sold 24 animals the number of leftover balloons were 164.

The difference of the number of items = 24 - 15 = 9 more animals sold

The difference of the leftover balloons = 200 - 164 = 36 balloons used

Now the number of her sold animals was = 33

and the left over balloons = 128

The number of sale was increased by 24 to 33 = 33 - 24 = 9 more animals

and the leftover balloons now 164 to 128 = 164 - 128 = 36 used

Therefore, we can see each sale of 9 balloon animals she used 36 balloons.

so Amira used for each balloon animal = $\frac{36}{9}$

= 4 balloons.

Amira used 4 balloons for each balloon animal.

5 0

2 years ago

Read 2 more answers

Find the x if the sequence 3, x, 4x/3 is (a)arithmetic and (b)geometric

jolli1 [7]

(a) When the sequence is arithmetic, sequential terms have a common difference.

... x - 3 = (4x/3) - x . . . . differences of sequential terms are equal

... (2/3)x = 3 . . . . . . . add 3-(1/3)x

... x = 9/2 . . . . . . . . . multiply by 3/2

(The arithmetic sequence is 3, 4.5, 6. The common difference is 3/2.)

(b) When the sequence is geometric, sequential terms have a common ratio.

... x/3 = (4x/3)/x . . . . . ratios of sequential terms are equal

... x^2 = 4x . . . . . multiply by 3x

... x = 4 . . . . . . . . divide by x. (the "solution" x=0 is extraneous)

(The geometric sequence is 3, 4, 16/3. The common ratio is 4/3.)

6 0

2 years ago

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc

stira [4]

Answer:

a. p(x<= 5) = .15 + .4 + .25 = .8

C. .4(4.2) = 1.68

5.4(1-.4) = 3.24

3.24 + 1.68 = 4.92 ,, 4.92 > 4.55 so short is better

Step-by-step explanation:

8 0

2 years ago

At a particular restaurant, each onion ring has 70 calories and each slider has 200 calories. A combination meal with onion ring

crimeas [40]

Answer:

3x + 6y

x = sliders

y = onion rings

Step-by-step explanation:

2:1 ratio of onion rings to sliders, add them 200+70+70 = 340,

then 1020/340 = 3, then input into an equation remembering the ratio of onion rings to sliders

7 0

2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

The probability, $P =0.0002$

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago