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s344n2d4d5 [400]
2 years ago
12

Plzzzzzz help. I have to waist so many points becouse peaple dont answer my question plzzzzzz help will give brainliest (pic dow

n below)
A model house that runs completely on renewable energy uses 222 windmills and 333 solar panels. Each windmill generates MMM kilowatt-hours (kWh) of energy per year, and each solar panel generates SSS kWh per year.
Which expressions can we use to describe how many kWh of energy the model house will output in 101010 years?
Choose 2 answers:

Mathematics
1 answer:
Ronch [10]2 years ago
5 0

Answer:

10(2M+3S)

20M+30S

Step-by-step explanation:

we know that

The number of kWh of energy that the model house generate per year is given by the sum of  kWh of energy generates by the windmills multiplied by the number of windmills, plus the  kWh of energy generates by the solar panels multiplied by the number of solar panels.

so

2M+3S

For 10 year

Multiply the expression above by 10

10(2M+3S)

Apply distributive property

20M+30S

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Pietro made 18 baskets during a basketball game.The number of 3 pointers are 3 more than half of the 2 point shots.how many type
blagie [28]

Total points is 23

<u>Explanation:</u>

Given:

Total number of baskets = 18

Let the number of 2 pointer shots be x

Let the number of 3 pointer shots be y

According to the question:

y = \frac{x}{2} + 3                  -1

The equation can be formed as:

\frac{x}{2} + 3 + x = 18

On solving this equation further we get:

\frac{x+6+2x}{2} = 18\\\\9x = 36\\\\x = 4

Putting the value of x = 4 in equation 1

y = \frac{x}{2}+3\\ \\y = \frac{4}{2} + 3\\\\y = 5

Points for 2 pointer shots = 4 X 2

                                        = 8

Points for 3 pointer shots = 5 X 3

                                        = 15

Total points = 8 + 15

                  = 23

Therefore, total points is 23

5 0
2 years ago
Your utility company charges 13 cents per kilowatt-hour of electricity. What is the daily cost of keeping lit a 75 watt light bu
Tresset [83]

we know that

1 Kw=1000 w

The company charges 13 cents per kilowatt-hour of electricity

13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw

Step 1

Find the cost for the light bulb

a) in one day

\frac{75}{1000} *12=0.9\ kw\  hour

Cost=0.13*0.9

Cost=$0.117

b) In a year

\frac{75}{1000} *12=0.9\ kw\  hour

0.9*365=328.5\ kw\  hour

Cost=0.13*328.5

Cost=$42.71

Step 2

Find the cost for the led bulb

a) in one day

\frac{15}{1000} *12=0.18\ kw\  hour

Cost=0.13*0.18

Cost=$0.0234

b) In a year

\frac{15}{1000} *12=0.18\ kw\  hour

0.18*365=65.7\ kw\  hour

Cost=0.13*65.7

Cost=$8.54

Step 3

Find the difference in cost

Save=42.71-8.54\\ Save=34.17 dollars

therefore

the answer is

34.17 dollars

3 0
2 years ago
Read 2 more answers
A company manufactures two products X and Y. Each product has to be processed in three departments: welding, assembly and painti
Tems11 [23]

Answer:

100x+120y = z

z= $ 63000

Step-by-step explanation:

Product               Welding          Assembly       Painting                Cont. to profit

X                              2x hours            3x hours          1xhour         =        $100x

Y                              3y hours            2y hours           1y hour        =       $120y

<u>                                                                                                 </u>

Total hours          1500 hours        1500 hours     550 hours

available

Let X represent product X

Let Y represent Product Y

2x + 3y = 1500

x + y = 550

y= 550-x

2x + 3(550-x) = 1500

2x + 1650- 3x = 1500

150 = x

y = 550-150

y = 400

Objective Function Z = 100x + 120y

Z = 100(150) + 120( 400)

Z = 15000+48000

Z = $63000

7 0
2 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15.
kicyunya [14]
In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.

In the second case we'd also subtract 1 from both sides, and would obtain
 |x-1|>14.

What would the graphs look like?

In the first case, the graph would be on the x-axis with "center" at x=1.  From this center count 14 units to the right, and then place a circle around that location (which would be at x=15).  Next, count 14 units to the left of this center, and place a circle around that location (which would be -13).  Draw a line segment connecting the two circles.  Notice that all of the solutions are between -13 and +15, not including these endpoints.

In the second case, x has to be greater than 15 or less than -13.  Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right.  None of the values in between are solutions.

4 0
2 years ago
Read 2 more answers
Felipe planted some seeds for a science project. One of his plants grew 6 2/7 inches in the first week, and then it grew 5 11/14
MatroZZZ [7]

Answer:

<em>The plant grew </em>12\frac{1}{14}<em> inches</em>

Step-by-step explanation:

<u>Operations with Fractions</u>

Felipe planted seeds for a science project. One of the plants grew 6 2/7 inches in the first week and 5 11/14 inches in the second week.

We are required to find the total growth during the two weeks. We have to find the sum of:

6\frac{2}{7}+5\frac{11}{14}

Let's convert both fractions to improper form:

6\frac{2}{7}+5\frac{11}{14}=6+\frac{2}{7}+5+\frac{11}{14}

Adding the integers:

6\frac{2}{7}+5\frac{11}{14}=11+\frac{2}{7}+\frac{11}{14}

Now we find the LCM of 7 and 14 is 14, thus:

6\frac{2}{7}+5\frac{11}{14}=11+\frac{4}{14}+\frac{11}{14}

6\frac{2}{7}+5\frac{11}{14}=11+\frac{15}{14}=11+\frac{14+1}{14}

6\frac{2}{7}+5\frac{11}{14}=11+1+\frac{1}{14}

6\frac{2}{7}+5\frac{11}{14}=12+\frac{1}{14}

Rewriting as a mixed number:

The plant grew 12\frac{1}{14} inches

8 0
2 years ago
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