The <em><u>correct answer</u></em> is:
Box 2
Explanation:
In these expressions, x represents the width of the box. We are asked about widths greater than 1; let's us 1.1 as an example:
Box 1:
3(1.1⁵) = 4.83153
Box 2:
4(1.1⁵)-(1.1⁴) = 6.44204 - 1.4641 = 4.97794
With a difference as small as a tenth, the volume of box 2 is larger. The larger the difference in width, the larger the difference in volume, and the volume of box 2 will be larger every time.
Answer:
R(x) is your answer
Step-by-step explanation:
Answer:
0.2611
Step-by-step explanation:
Given the following information :
Normal distribution:
Mean (m) length of time per call = 3.5 minutes
Standard deviation (sd) = 0.7 minutes
Probability that length of calls last between 3.5 and 4.0 minutes :
P(3.5 < x < 4):
Find z- score of 3.5:
z = (x - m) / sd
x = 3.5
z = (3.5 - 3.5) / 0.7 = 0
x = 4
z = (4.0 - 3.5) / 0.7 = 0.5 / 0.7 = 0.71
P(3.5 < x < 4) = P( 0 < z < 0.714)
From the z - distribution table :
0 = 0.500
0.71 = very close to 0.7611
(0.7611 - 0.5000) = 0.2611
P(3.5 < x < 4) = P( 0 < z < 0.714) = 0.2611
Answer:
The price would be decreased by 18 bozats
Step-by-step explanation:
The following information is given in the question
x = number of kilograms of snig sold
P = Price per kilogram
And, the equation is
p = 300 - 18x
Now if an extra kilogram is sold so it should be x+1
Now the new price is
New price = 300 - 18(x + 1)
= 300 - 18x - 18
Therefore the price would be decreased by 18 bozats
Answer:
Original sum of money = $2246.51
Step-by-step explanation:
Interest = $96.60
Interest is compounded 6 times in a year ; n = 6
time = 1 year ; Rate of interest (r) = 4.2%
Interest = Future Value - Principal Value ...........(1)
![\text{Future Value = }Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}\\\\\text{Substituting this value in equation (1) , We get }\\\\Interest=Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}-Principal\\\\\implies 96.60=Principal[\cdot (1+\frac{4.2}{100\times 6})^{6\cdot 1}-1]\\\\\implies Principal=\$2246.51](https://tex.z-dn.net/?f=%5Ctext%7BFuture%20Value%20%3D%20%7DPrincipal%5Ccdot%20%281%2B%5Cfrac%7Br%7D%7B100%5Ctimes%20n%7D%29%5E%7Bn%5Ccdot%20t%7D%5C%5C%5C%5C%5Ctext%7BSubstituting%20this%20value%20in%20equation%20%281%29%20%2C%20We%20get%20%7D%5C%5C%5C%5CInterest%3DPrincipal%5Ccdot%20%281%2B%5Cfrac%7Br%7D%7B100%5Ctimes%20n%7D%29%5E%7Bn%5Ccdot%20t%7D-Principal%5C%5C%5C%5C%5Cimplies%2096.60%3DPrincipal%5B%5Ccdot%20%281%2B%5Cfrac%7B4.2%7D%7B100%5Ctimes%206%7D%29%5E%7B6%5Ccdot%201%7D-1%5D%5C%5C%5C%5C%5Cimplies%20Principal%3D%5C%242246.51)
Hence, the original sum of money borrowed = $2246.51