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Irina18 [472]
2 years ago
15

An investment firm offers three types of equity investments,

Mathematics
2 answers:
Free_Kalibri [48]2 years ago
8 0

Answer:

7.1

Step-by-step explanation:

A, B, and C. Of the firm's clients, 30% invest in A, 50% invest in B, and 20% invest in C. The rates of return are 10%, 6%, and 7% for A, B, and C, respectively. 7.1 plato

Fudgin [204]2 years ago
5 0

Answer:

<u>The expected value of the total return rate for the firm's clients is C. 7.4%</u>

Step-by-step explanation:

1. Let's review all the information given for solving the question:

Type of equity investments = A, B and C

Percentage of investment in each type of equity = 30% in A, 50% in B and 20% in C.

Rates of return of each type of equity investment = 10% for A, 6% for B and 7% for C.

2. Let's find the expected value of the total return rate for the investment firm:

Return rate for each type of investment = Percentage of investment * Rate of return

For A = 30% * 10% = 0.3 * 0.1  = 0.03

For B = 50% * 6% = 0.5 * 0.06 = 0.03

For C = 20% * 7% = 0.2 * 0.07 = 0.014

Total return rate = Return rate for A + Return rate for B + Return rate for C

Total return rate = 0.03 + 0.03 + 0.014 = 0.074

<u>Total return rate = 0.074 * 100 = 7.4%</u>

<u>The expected value of the total return rate for the firm's clients is C. 7.4%</u>

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Answer:

Farhan had 9 comic books

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W + F = 36

W = 3F

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1 year ago
A linear regression equation is calculated for a sample of n = 20 pairs of X and Y values.
Nata [24]

Answer: B) 18

Step-by-step explanation:

The degree of freedom for Standard error or df(Residual) is the sample size minus the number of estimated parameters ,.

df= n - p  , where n= sample size , p = number of parameters.

According to the given problem , we have

Sample size : n=20

Number of parameters (x and y ): p= 2

Then, the df value for the standard error of estimate will be :

df= n-p =20-2=18

Thus , the df value for the standard error of estimate is 18 .

Hence, the correct answer is B) 18 .

3 0
2 years ago
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles
Ugo [173]

By definition, the average rate of change is given by:

AVR = \frac{f(x2)-f(x1)}{x2-x1}

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2

Evaluating for x = 3:

f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18

Then, the AVR is:

AVR = \frac{18-(-2)}{3-(-2)}

AVR = \frac{18+2}{3+2}

AVR = \frac{20}{5}

AVR = 4


For f (x) = 3x - 8:

Evaluating for x =4:

f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4

Evaluating for x = 5:

f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7

Then, the AVR is:

AVR = \frac{7-4}{5-4}

AVR = \frac{3}{1}

AVR = 3


For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15

Evaluating for x = 4:

f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8

Then, the AVR is:

AVR = \frac{8-15}{4-(-3)}

AVR = \frac{-7}{4+3}

AVR = \frac{-7}{7}

AVR = -1


For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4

Evaluating for x = 1:

f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4

Then, the AVR is:

AVR = \frac{-4-(-4)}{1-(-1)}

AVR = \frac{-4+4}{1+1}

AVR = \frac{0}{2}

AVR = 0


Answer:

from the greatest to the least value based on the average rate of change in the specified interval:


f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]


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Use the X method to find the solutions of<br><br> 6x2 + 2x – 20 = 0
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