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Yuri [45]
2 years ago
12

In a geometric series, the first term is 108 and the common ratio is \frac{2}{3}. Find the sum of the first 8 terms.

Mathematics
1 answer:
Valentin [98]2 years ago
7 0

Answer:

311.36

Step-by-step explanation:

For  a geometric series sum of first n terms is a(1-r^n)/(1-r)

if r is less than 1.

where a is the first term and r is the common ratio.

____________________________\

given

a = 108

r = \frac{2}{3}.

n = 8

thus , sum of n term is

a(1-r^n)/(1-r)\\=>108(1-(2/3)^8)/(1-2/3)\\=> 108 (1 - 256/6561)/1/3\\=> 108(6561-256)/ 6561/1/3\\=> 108(6305)/2187\\=>311.36

Thus sum of first 8 terms is 311.36

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Answer:

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