Question

A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4 °F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5°F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation. Complete the steps below to solve the problem

Answer 1

Answer:

At the elevation 617.5 feet below the sea level temperature of the water was $61\frac{1}{20}$°F

Step-by-step explanation:

At 502.5 feet below the sea level temperature of the water is $63\frac{1}{4}$°F

When submarine dives down 115 feet deeper, water temperature drops by $2\frac{1}{5}$°F

Elevation after the submarine dove = -502.5 - 115 = -617.5 feet

This negative sign represents the elevation below the sea level.

And the temperature will be = $63\frac{1}{4}-2\frac{1}{5}$

                                               = $\frac{253}{4}-\frac{11}{5}$

                                               = $\frac{1265-44}{20}$

                                               = $\frac{1221}{20}$

                                               = $61\frac{1}{20}$°F

Therefore, at the elevation 617.5 feet below the sea level temperature of the water was $61\frac{1}{20}$°F

Answer 2

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 = 
63 - 2 = 61
1/4 - 1/5 = 5/20 - 4/20 = 1/20
so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F