Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and
of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>
Let be "s" the total number of seats in the Stalls.
The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is
.
Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

Solving for "s", we get:

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:
We know that
of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

Therefore, the total number of seats that were occupied las Friday is:
Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

Solving for "p", we get:

Answer:
Tax for Italian Salad=$0.20
Tax for Lasagna= $0.43
Tax for Spaghetti =$0.21
Tax for Fettuccini Alfredo =$0.36
Step-by-step explanation:
Hi, to answer this question we have to multiple the price of each item by the tax percentage in decimal form (divided by 100):
Italian Salad =$3.99
- Tax for Italian Salad= 3.99 x (5/100) = 3.99 x 0.05 =$0.20
Lasagna =$8.50
- Tax for Lasagna= 8.50 x (5/100) = 8.50 x 0.05 =$0.43
Spaghetti =$4.29
- Tax for Spaghetti = 4.29x (5/100) = 4.29 x 0.05 =$0.21
Fettuccini Alfredo =$7.17
- Tax for Fettuccini Alfredo = 7.17 x (5/100) = 7.17 x 0.05 =$0.36
Feel free to ask for more if needed or if you did not understand something.
Hey!
Your answer would be:
x-intercept: The number of cups of lemonade that must be sold to break even.
y-intercept: Money spent before the sale of the first cup of lemonade.
Took the test <3
Answer:
81%
Step-by-step explanation:
Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.
Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:
F = 100% - 19% = 81%