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Phoenix [80]
2 years ago
11

(2 thousands 7 tens) times 10

Mathematics
1 answer:
kodGreya [7K]2 years ago
8 0

You can multiply the digits or the place value. Either way, you will get the same result.

(2 thousands, 7 tens) × 10 =

... (20 thousands, 70 tens)

or

... (2 ten-thousands, 7 hundreds)

You might be interested in
Suppose flaws (cracks, chips, specks, etc.) occur on the surface of glass with density of 3 per square meter. What is the probab
DiKsa [7]

Answer:

0.047

Step-by-step explanation:

Given that poisson distribution with mean m, for 0.5 square meter =1.5

Then the formula for finding the probability =

P[k] = (e^-m * m^k) k!

Hence we have

P[4] =[ (e^-1.5) * (1.5^4)] ÷ 4 * 3 * 2 * 1

= (0.2231301601 * 5.0625) ÷ 24

=( 1.12944375) ÷24

= 0.04706

≈ 0.047

Hence, the final answer is 0.047

8 0
2 years ago
The commission earned on the sale of a car can be represented by the equation c(p)=250+0.02p where c represents the commission a
ch4aika [34]

Answer:

1) His total commission is $1,234.3

2) The purchase of the car is $24,790.

Step-by-step explanation:

1) 21640*0.02= 432.8+ 250= 682.8

15075*0.02= 301.5+ 250= 551.5

682.8+ 551.5= 1,234.3

2) 745.8- 250= 495.8/ 0.02= 24,790

6 0
2 years ago
Read 2 more answers
John has two jobs. For daytime work at a jewelry store he is paid
djyliett [7]

Given Information:

John's mean monthly commission = μ = $10,000

Standard deviation of monthly commission = σ =  $2,000

Answer:

P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%

The probability that John's commission from the jewelry store is  between $9,000 and $11,000 is 38.3%

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.  

We want to find out the probability that John's commission from the jewelry store is  between $9,000 and $11,000?

P(9,000 < X < 11,000) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(9,000 < X < 11,000) = P( \frac{9,000 - 10,000}{2,000} < Z < \frac{11,000 - 10,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( \frac{-1,000}{2,000} < Z < \frac{1,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( -0.5 < Z < 0.5 )\\\\P(9,000 < X < 11,000) = P( Z < 0.5 ) - P( Z < -0.5 ) \\\\

The z-score corresponding to 0.50 is 0.6915

The z-score corresponding to -0.50 is 0.3085

P(9,000 < X < 11,000) = 0.6915 - 0.3085 \\\\P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%

Therefore, the probability that John's commission from the jewelry store is  between $9,000 and $11,000 is 38.3%

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.4, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.50 then go for 0.00 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

4 0
2 years ago
Suppose that on a certain examination in advanced mathematics, students from univer sity A achieve scores that are normally dist
harkovskaia [24]

Answer:

P(z>-1.768)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the scores for the univerisity A, and we know that:

X \sim N (\mu = 625,\sigma =\sqrt{100}= 10)

Let Y the scores for the univerisity B, and we know that:

Y \sim N (\mu = 600,\sigma =\sqrt{150}= 12.25)

We select a sample size of size n=2, and since the distirbution for X is normal then the distribution for the sample mean would be given by:

\bar X \sim N(\mu=625, \frac{\sigma}{\sqrt{n}}=\frac{10}{\sqrt{2}}=7.07)

And for the univeristy B we select a sample of n=3

\bar Y \sim N(\mu=600, \frac{\sigma}{\sqrt{n}}=\frac{12.25}{\sqrt{3}}=7.07)

Since both sample means are normally distributed then the difference Z= \bar X- \bar Y is also normal distributed with the following parameters:

Z= \bar X -\bar Y \sim N(\mu_Z=625-600=25, \sigma_z= \sqrt{100+100}=14.14)

And we want this probability:

P(Z>0)

And we can use the z score given by:

Z= \frac{z -\mu_z}{\sigma_z}

And if we replace we got :

Z= \frac{0-25}{14.14}=-1.768

And if we find the probability using the normla standard table or excel we got:

P(z>1.768) =1-P(Z

3 0
2 years ago
Boy Scout Troop 2 went backpacking in the Sierras. The scouts hiked 5 1/2 hours each day for 4 days. If their average speed was
KIM [24]

Given :

Time they traveled in a day , t=5\dfrac{1}{2}=\dfrac{11}{2}\ hours .

Average speed , s=1\dfrac{3}{4}=\dfrac{7}{4}\ mph .

To Find :

How far did they hike altogether in 4 days .

Solution :

We know , distance covered is given by :

d=s\times t \\\\d=\dfrac{7}{4} \times \dfrac{11}{2}\ miles\\\\d=\dfrac{77}{8}\ miles

So , distance covered in 4 days is :

D=\dfrac{77}{8}\times 4\ miles\\\\D=38.5\ miles

Therefore , distance they hike in 4 days is 38.5 miles .

Hence , this is the required solution .

7 0
2 years ago
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