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2 years ago

Matias stepmother uses 30% off coupon to buy the ingredients for huevos rancheros she spends $28

Mathematics

2 answers:

fredd [130]2 years ago

8 0

The original total of the ingredients was 40 dollars

lina2011 [118]2 years ago

8 0

Answer:

$40

Step-by-step explanation:

To determine the regular price r of the ingredients before the discount, we have to consider that $28 represents 70% of the regular price as this amount has a 30% discount and with that, find the price that represents 100%:

$28 → 70%

r ← 100%

r=($28*100%)/70%= $40

The regular price r of the ingredients before the discount is $40.

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What’s the domain and range? An airplane travels at 565 mph.

viktelen [127]

Answer:

Domain:

The domain of this can be any value between 0 to 565 miles per hour

Range:

The reasonable range can be the distance traveled which can be from 0 to 13,560 miles (no plane travel is longer than 24 hours, we assume).

Step-by-step explanation:

Domain is the input, set of x values for the function.

Range is the output, set of y values for the function.

This isn't a function essentially, but it is given that an Airplane travels at 565 miles per hour.

We can say that the domain will be the speed of the airplane and the range would be the distance it travels.

Domain:

The domain of this can be any value between 0 to 565 miles per hour

Range:

The reasonable range can be the distance traveled which can be from 0 to (565*24=13,560 miles) 13,560 miles (no plane travel is longer than 24 hours, we assume).

4 0

2 years ago

Find Four Numbers that form a geometric progression such that the second term is less than the first by 35, and the third term i

Olegator [25]

Answer:

-35/3, -140/3, - 560/3, -2240/3
7, -28, 112, - 448

Step-by-step explanation:

The terms are:

a₁, a₂, a₃, a₄

Given:

a₁ = a₂ + 35
a₃ = a₄ + 560

Use the nth term formula:

a₂ = a₁r
a₃ = a₁r²
a₄ = a₁r³

Substitute:

a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
a₁r² = a₁r³ + 560 ⇒ a₁(1 - r)r² = 560

Divide the second equation by the first:

r² = 560/35
r² = 16
r = √16
r = ± 4

Use the first equation to find the first term:

a₁( 1 ± 4) = 35
1. a₁ = 35/-3 = -35/3
2. a₁ = 35/5 = 7

We have two sequences:

r = 4

-35/3, -140/3, - 560/3, -2240/3

r = -4

7, -28, 112, - 448

8 0

2 years ago

The author believes we are “endangering our health by not using the metric system.” Do you agree or disagree and why?

crimeas [40]

I agree with the author. By using the metric system we know the exact amount of a medicine we took, whether it's in mg or mL. This way every doctor can prescribe the same amount.
If we were using some other units this may not be the case. For example, british and american inch were different until 1950's.

Example: if you go to a surgery and a doctor needs to cut "1 inch from the left part" it may cause a mistake as this unit is different in different countries. But if he needs to cut "2.5 cm from the left part" he knows exactly where to cut.

Another benefit of using metric system is that it is being used in almost every country in the world.

8 0

2 years ago

A rectangular parking lot is 12 meters wide and 9 meters long. The dimensions of the rectangular base of the building next door

xenn [34]

Answer:

I just fart my pants til tehy explde god so ez kid

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [infinity] e−stf(t) dt 0 is said to be the

Anastaziya [24]

Answer:

The laplace transform is $\frac{2}{(s+6)^3}$

Step-by-step explanation:

We will solve this problem by applying the laplace transform properties (their proofs are beyond the scope of this explanation).

Consider first the function f(t) = 1. By definition of the laplace transform, we have

$F(s) = \int_{0}^{\infty}f(t)e^{-st}dt$

when f(t) = 1 we get

$F(s) = \int_{0}^{\infty}e^{-st}dt = \left.\frac{-e^{-st}}{s}\right|_{0}^{\infty} = \frac{1}{s}$

We will apply the following properties: Define L(f) as applying the laplace transform

$L(e^{at}f(t)) = F(s-a)$ (this means, multiplying by an exponential corresponds to a shift in the s parameter of the transform of f)

$L(t^nf(t)) = (-1)^n\frac{d^n F}{ds^n}$ (this is, multypling by $t^n$ is equivalent to taking the n-th derivative of the transform.

We are given the function $g(t) = t^2e^{-6t}\cdot 1$ . Since the transform of the constant function 1 is 1/s, by applying the first property we get

$L(e^{-6t}\cdot 1 ) = \frac{1}{s+6}$

By applying the second property we get

$L(g(t)) = L(t^2 e^{-6t} \cdot 1) = (-1)^2\frac{d^2}{ds^2}(\frac{1}{s+6}) = \frac{2}{(s+6)^3}$

3 0

2 years ago