Question

John had a roll containing 24 2/3 feet of wrapping paper. He wants to divide it into 11 pieces. First, though, he must cut off 5/6 foot because it was torn. How long will each piece be?

Answer 1

Given

John had a roll containing of wrapping paper  

$=24\tfrac{2}{3}$

First, he must cut off 5/6 foot because it was torn.

He wants to divide it into 11 pieces.

To proof

As given in question

John had a roll containing of wrapping paper

$=24\tfrac{2}{3}$

$=\frac{74}{3}$    ( solving the mixed fraction form)

 First, though, he must cut off 5/6 foot

than we get

$= \frac{74}{3} - \frac{5}{6}$

Taking the L.C.M of 3 and 6 is 6

$=\frac{148-5}{6}$

$=\frac{143}{6}$

=23.83 feet (approx)

He wants to divide it into 11 piece

length of the each piece

$=\frac{23.83}{11}$

length of the each pieces be 2.16 feet ( approx)

Hence proved

Answer 2

We are given a total size of 24 2/3 feet of wrapping paper. Convert this into fraction of denominator 6:

total paper = 24 2/3 = 74/3 = 148/6 feet

 

Subtract 5/6 foot:

remaining paper = 148/6 – 5/6 = 143/6 feet

 

Divide by 11:

each piece = (143/6) ft / 11 = 143/66  ft = 2.17 ft