By definition, the perimeter of a square is given by:

Where,
L: length of the sides of the square.
When the sides of the square are tripled, the equation changes as follows:

Then, rewriting the equation we have:


Where,
P: perimeter of the original square.
Therefore, we can conclude that the perimeter is tripled.
Answer:
The perimeter of the square is tripled.
Answer:
The Point C shows the location of 5-2i in the complex plane: 5 points to the right of the origin and 2 points down from the origin.
Step-by-step explanation:
We have the complex number 5-2i and we have to show the location of the point that represents that number in the complex plane
In the complex plane the real numbers are located in the horizontal axis, increasing to the right. The positives real numbers are at the right of the origin and the negatives to the left.
The complex numbers are located in the vertical axis, with the positives over the origin and the negatives below the origin.
This complex number 5-2i is the sum of a real part (5) and a imaginary part (-2i), so the point will be 5 units rigth on the horizontal axis (for the real part) and 2 units down in the vertical axis (for the imaginary part).
Answer:
Step-by-step explanation:
Information provided
n=100 represent the random sample taken
X=21 represent the number of bags overfilled
estimated proportion of overfilled bags
is the value that we want to test
z would represent the statistic
Hypothesis
We need to conduct a hypothesis in order to test if the true proportion of overfilled bags is higher than 0.15.:
Null hypothesis:
Alternative hypothesis:
The statistic for this case is:
(1)
And replacing the info given we got:
Answer:
the correct anser is 0.0000563
Step-by-step explanation:
you move the decimal point to the left 5 spaces because it is negative
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.