Given the following formula, solve for v. s = 1/2a^2v + c

Mathematics

2 answers:

dexar [7]1 year ago

8 0

Answer:

Step-by-step explanation:

correct

weeeeeb [17]1 year ago

7 0

Since there is no initial condition, the exact value of v cannot be determined, but you can set the equation up for a general evaluation of the situation.

s = 1/2a^2*v+c

First you need to subtract c from both sides to get

s-c = 1/2a^2*v

then you can just divide both sides by 1/2a^2 to get v

(2(s-c))/a^2=v

when dividing a fraction, such as 1/2, make sure to keep in mind that you're really multiplying the flipped version, so that dividing by 1/2 means multiplying by 2.

You might be interested in

A tanker that ran aground is leaking oil that forms a circular slick about 0.2 foot thick. To estimate the rate dV/dt (in cubic

blondinia [14]

Answer:

dV/dt = 155.74 ft^3/minute

Step-by-step explanation:

Volume V = Area × thickness

Area A= πr ^2

Thickness = 0.2 ft

Volume V = 0.2A = 0.2πr^2

V = 0.2πr^2

Differentiating both sides;

dV/dt = 0.2π × 2r dr/dt = 0.4πr.dr/dt

Given;

r = 400 ft

dr/dt = 0.31 ft/minute

π = 3.14

Substituting the values

dV/dt = 0.4πr.dr/dt = 0.4 × 3.14 × 400 × 0.31

dV/dt = 155.74 ft^3/minute

8 0

1 year ago

Read 2 more answers

G A professor has two light bulbs in his garage. When both are burned out, they are replaced, and the next day starts with two w

Aneli [31]

Answer:

2/7 or 0.2857

Step-by-step explanation:

The expected time before the first bulb burns out (two bulbs working) is given by the inverse of the probability that a bulb will go out each day:

$E_1 = \frac{1}{0.02}=50\ days$

The expected time before the second bulb burns out (one bulb working), after the first bulb goes out, is given by the inverse of the probability that the second bulb will go out each day:

$E_2 = \frac{1}{0.05}=20\ days$