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Elenna [48]
2 years ago
11

At Northwest Highschool, there are 1472 students in the junior class and 1012 students in the senior class. To let the juniors w

ork with more experienced students, the teachers want to assign the students to committees with the same same number of juniors in each committee and the same number of seniors in each committee. (For example, there might be 2 juniors and 3 seniors in every committee). What is the largest number of committees that can be formed?
A: 23 committees
B: 4 committees
C: 368 committees
D: 92 committees

Need this ASAP please
Mathematics
1 answer:
Cloud [144]2 years ago
5 0
The awnser would be A
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From 2000-2003, students were tested by the state in four major subject areas of math, science, English and social studies. The
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No way to tell . . . . . we can't see the chart below.
It must be WAY down there where the sun don't shine.
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A basket of 40 pairs of pliers at a discount hardware store includes 5 pairs of 6-inch pliers. A second basket contains 20 hamme
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First, add all the numbers together, which is 68. Then divided 100 by 68, which gives you the number 1.47, and that's your answer.
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Terry has a large bucket of water. He uses 2.25 gal to
Novosadov [1.4K]

Answer:

I think the answer is  3.47

Step-by-step explanation:

Terry starts out with 2.25 gallons, and he uses 1.33 so you subtract these so he has .92 gallons left. He adds 4.8 gallons so you add 4.8 to .92 and get 5.72 gallons total in the bucket... If the question is asking how much change between the beginning and end I would say 5.72- 2.25= 3.47

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Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit. (Hint: Assume that
Vadim26 [7]
So... if you notice the picture below

each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle

now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors

hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle

so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3

so    \bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}\\\\
-----------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad r=radius\\\\
\textit{area of half a circle}\\\\
A=\cfrac{\pi r^2}{2}\\\\
-----------------------------\\\\

\bf \textit{now, let us use the side of 6, and radius of 3}
\\\\\\

\begin{array}{clclll}
\cfrac{6^2\sqrt{3}}{4}&-&\cfrac{\pi 3^2}{2}\\
\uparrow &&\uparrow \\
triangle's&&semi-circle's
\end{array}\impliedby \textit{area of shaded area}\\\\
-----------------------------\\\\
\boxed{\cfrac{36\sqrt{3}}{4}-\cfrac{9\pi }{2}}

you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format

8 0
2 years ago
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Show that b^2 is greater than equal to or less than ac, according as a, b, c are in A.P., G.P.
ValentinkaMS [17]

Answer/Step-by-step explanation  (ac > b² or b² < ac. )

A/c to question, we have to show:-

b² >ac in A.P ........ (1)

b² = ac in G.P .....(2)

b² < ac in H.P. ..... (3)

b = a+c/2 (A.P)

b = √ac ( G.P)

b = 2ac/a+c (H.P)

In A.P :

b² > ac = b² - ac

= (a+c/2)² - ac

= (a²+2ac+c²/4) - ac  = a² + 2ac + c² - 4ac / 4

= a² - 2ac + c² / 4  = ( a - c ) ² / 4 > 0  Hence, b²>ac

In G.P:-

b = √ac

Hence, b² = ac

In H.P :-  b² < ac = ac > b²  = ac - b²  = ac - ( 2ac / a+c)

= ac(a+c) - 2ac / a+c

= a²c + ac² - 2ac / a+c

= ac(2ac - 2) / a+c > 0

Hence, ac > b² or b² < ac.

5 0
1 year ago
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