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2 years ago

Sally paid $2.40 for 4 ounces of cinnamon. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound

Mathematics

2 answers:

barxatty [35]2 years ago

8 0

Answer:

$12.80 per pound

Step-by-step explanation:

Since there are 16 ounces in 1 pound, we multiply $0.80 by 16 ounces to find how much cinnamon costs per pound. The answer is $12.80.

Hope this helped, Have a Wonderful Day!!

Marina86 [1]2 years ago

3 0

Answer:

For 1 pound that would $9.20

Step-by-step explanation:

Since there are 16 ounces in 1 pound and Sally paid for 4 with $2.40, what you have to do is take that total and times it by how many you need to times the ounces by to get a pound which would be 4.

4 x 4 = 16

So, that means to get the total for 1 pound you would have to do

$2.40 x 4

Which would equal

$9.20

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Answer:

a) 51.4

b) answer attached

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2 years ago

The inequality describes the range of monthly average temperatures T in degrees Fahrenheit at a certain location. Find an equiva

kolezko [41]

Answer:

Now if the high and low monthly average temperatures satisfy the inequality, then the , monthly averages are always within 22 degrees of 43°F.

Step-by-step explanation:

The inequality describes the range of monthly average temperatures T in degrees Fahrenheit at a certain location.

The inequality expression is given as:

$|T-43|\leq 22$

now this expression could also be expressed as:

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Now if the high and low monthly average temperatures satisfy the inequality, then the , monthly averages are always within 22 degrees of 43°F.

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2 years ago

A dentist is making identical dental care bags for patients using 56 tubes of toothpaste, 112 packets of floss, and 85 toothbrus

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Answer : Greatest number of identical dental care bags the dentist can make with the least items leftover is 1.

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Number of toothbrushes = 85

So, Greatest number of identical dental care bags the dentist can make with the least amount of items leftover from toothbrush = H.C.F of 56,112, 85= 1 ( ∵ as they are coprime to each other )

Since there is no common factor among 56,112,85 but there is common factor between 56 and 112 i.e. 56 remaining bags from toothbrushes will be 85-56=29 .

So we consider 28 ,

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112 can be written as 28×4 and

84 can be written as 28× 3

So, there can be 28 bags in which all the three materials can be present and there is no leftover from toothpaste and floss but there is leftover from toothbrushes only as we consider 84 instead of 85 to get divisible by 28 so we get the common factor easily.

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