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anyanavicka [17]
1 year ago
6

In a large city, 46% of adults support the local football team building a new stadium. If a poll is taken from a random sample o

f 80 adults in the large city, which of the following properly describes the sampling distribution of the sample proportion of adults who support the stadium?
A) Mean: 36.8, Sigma P-hat: 4.46, the distribution is approximately normal.
B) Mean: 36.8, Sigma P-hat: 4.46, shape of the distribution is unknown.
C) Mean: 0.46, Sigma P-hat: 0.056, the distribution is approximately normal.
D) Mean: 0.46, Sigma P-hat: 0.056, shape of the distribution is unknown.
E) Mean: 43.2, Sigma P-hat: 4.46, the distribution is binomial.
Mathematics
1 answer:
elixir [45]1 year ago
8 0
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The matrices must be the same size

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A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot
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Answer:

a) p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545

0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.  

5 0
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The diagram shows a logo made from three circles
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Answer:

Use the formula π*(r^2) where r is radius

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Area of middle circle=153.93804

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Percentage of middle circle with small circle = (153.93804/314.1592654)*100= 48.999999999999 approx= 49%

Percentage of small circle alone = (78.53981634/314.1592654)*100

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So 51%= big circle alone

And 51%+25%= 76%

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To Find :

Net worth of Rachel.

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Therefore, net worth of Rachel is $ 363587.

Hence, this is the required solution.

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If D is the midpoint of GH, then GH equals 2(DH) = 16
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