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Tamiku [17]
1 year ago
10

Lori buys a $1500 certificate of deposit (CD) that earns 6% interest that compounds monthly. How much will the CD be worth in 10

years?
Mathematics
1 answer:
OlgaM077 [116]1 year ago
4 0

The CD will worth in $2729.09 after 10 years.

Solution:

Principal (P) = $1500

Rate of interest (r) = 6%

                              $=\frac{6}{100}

                             = 0.06

Time (t) = 10 years

Compounded monthly

Number of times interest applied per time period

n = 12

A = Total amount

Compound interest formula:

$A=P\left(1+\frac{r}{n}\right)^{n t}

$A=1500\left(1+\frac{0.06}{12}\right)^{12\times 10}

$A=1500\left(\frac{12+0.06}{12}\right)^{120}

$A=1500\left(\frac{12.06}{12}\right)^{120}

A=2729.09

The CD will worth in $2729.09 after 10 years.

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Answer:

H0 ; μ ≤ 4 pCi/L

Ha ; μ > 4 pCi/L

The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L

H0 ; μ ≤ 4 pCi/L

The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.

Ha ; μ > 4 pCi/L

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L

H0 ; μ ≤ 4 pCi/L

The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.

Ha ; μ > 4 pCi/L

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Step-by-step explanation:

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From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that ag
Jlenok [28]

Answer:

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.      

Step-by-step explanation:

1) Data given and notation      

\bar X=18.1 represent the mean age when smokers first start to smoke varies  

s=1.3 represent the standard deviation for the sample  

\sigma=2.1 represent the population standard deviation  

n=37 sample size      

\mu_o =5.7 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean starting age is at least 19, the system of hypothesis would be:      

Null hypothesis:\mu\geq 19      

Alternative hypothesis:\mu < 19      

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:      

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

z=\frac{18.1-19}{\frac{2.1}{\sqrt{37}}}=-2.607      

Calculate the P-value      

Since is a one-side lower test the p value would be:      

p_v =P(z  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we to reject the null hypothesis, and the the actual mean starting age of smokers is significantly lower than 19.      

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Answer:

Step-by-step explanation:

To find the Taylor series of sinc(x) we will use the taylor series of sin(x). We have that

\sin(x) = \sum_{n=0}^{\infty}\frac{(-1)^n x^{2n+1}}{(2n+1)!}

which is the taylor series expansion based at 0. Then for x\neq 0, by dividing both sidex by x, we have that

\text{sinc}(x) = \frac{\sin(x)}{x}= \sum_{n=0}^{\infty}\frac{(-1)^n x^{2n}}{(2n+1)!}

which is the taylor series expansion for the sinc function. Since the series of sine converges for every value of x. Then the taylor series of sinc converges for every value of x, but 0.

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