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2 years ago

Solve for $a$: $3a-7(3-a)=5$. Express your answer as a common fraction in simplest form.

Mathematics

1 answer:

SashulF [63]2 years ago

3 0

Answer:

2.6

Step-by-step explanation:

just put one part of the equation in y1 and the other in y2 and hit 2nd trace 5 an hit enter 4 times

then it will bring a graph hit enter 3 time again and it will show u the answer at the bottom left

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Marquis used the steps below to find the solution to the inequality Negative 5.6 greater-than-or-equal-to x + 3.6.

Taya2010 [7]

Answer:3.9

Step-by-step explanation:

you have to add the decimal to the exponent

5 0

2 years ago

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If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?

Nuetrik [128]

The variation would be x5. 4*5=20

6 0

1 year ago

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Frank had hip replacement surgery and was given a prescription with instructions to take a 200 milligrams (mg) tablet three time

oksian1 [2.3K]

Answer:10,500

Step-by-step explanation:

200 x 3= 500

500 x 21 = 10,500

3 0

1 year ago

8. Finley has 152 yellow, red, and blue marbles in a bag. He has seven more red marbles than yellow marbles, and three times as

DochEvi [55]

Let number of yellow marbles = x

Let number of red marbles = y

Let number of blue marbles = z

Given that Finley has 152 yellow, red, and blue marbles in a bag.

So we get equation:

x+y+z=152...(i)

"He has seven more red marbles than yellow marbles" means:

y=x+7...(ii)

"three times as many blue marbles as yellow marbles." means:

z=3x...(iii)

Now we just need to solve those equations to find the answer.

Plug (ii) and (iii) into (i)

x+(x+7)+(3x)=152

x+x+7+3x=152

Which looks similar to choice (B)

5x+7=152

5x=145

x=29

Hence final answer is choice B.

Required equation is

x+x+7+3x=152

Number of yellow marbles = 29

5 0

2 years ago

The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va

Firlakuza [10]

Answer:

The probability is $P(\= X < 33) = 0.8531$

The probability is $P(\= X > 30) = 0.3520$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 28.29$

The standard deviation is $\sigma = 33.493$

The sample size is $n = 56$

Generally the standard error for the sample mean $(\= x )$ is mathematically evaluated as

$\sigma _{\=x} = \frac{\sigma}{\sqrt{n} }$

substituting values

$\sigma _{\=x} = \frac{33.493}{\sqrt{56} }$

$\sigma _{\=x} = 4.48$

Apply central limit theorem[CLT] we have that

$P(\= X < 33) = [z < \frac{33 - \mu }{\sigma_{\= x}} ]$

substituting values

$P(\= X < 33) = [z < \frac{33 - 28.29 }{4.48} ]$

$P(\= X < 33) = [z < 1.05 ]$

From the z-table we have that

$P(\= X < 33) = 0.8531$

For the second question

Apply central limit theorem[CLT] we have that

$P(\= X > 30 ) = [z > \frac{30 - \mu }{\sigma_{\= x}} ]$

substituting values

$P(\= X < 33) = [z > \frac{30 - 28.29 }{4.48} ]$

From the z-table we have that

$P(\= X < 30) = 0.6480$

Thus

$P(\= X > 30) = 1- P(\= X < 30) = 1- 0.6480$

$P(\= X > 30) = 0.3520$

3 0

2 years ago