What is the sum? 3/8 +7/16 A) 5/12 B) 13/16 C) 7/8 D) 1 3/16

2 answers:

7 0

It is B. It’s B because you would have to multiply 3/8 by 2, which is 6/16. Now once you add 6/16 and 7/16 the sum is 13/16.

Firdavs [7]2 years ago

5 0

Double the first fraction so that it has the same denominator as the second (3/8) x 2 = 6/16, then add 6+7 = 13, so your answer would be B) 13/16

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2.314 divided by 1.3

kirza4 [7]

1.78 is the correct answer.

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2 years ago

Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t

Ber [7]

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable X is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable X follows an Exponential distribution with mean, μ = 4 minutes.

The probability density function of X is:

$f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0$

The parameter of the exponential distribution is:

$\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25$

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx$

$=0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821$

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

3 0

2 years ago

Dying for help please failing mathh

JulsSmile [24]

You might want to stick to at most five questions at once, makes it easier for the rest of us. :)

17. T has a vertical line of symmetry (along the center line).
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21. Every dilation has a center (where it's dilated from) and a scale factor (how much it's dilated).
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26. This is a reflection.

Need clarification on anything?

4 0

2 years ago

Read 2 more answers

Harper knows he is 50 yards from school. The map on his phone shows that the school is 34 inch from his current location. How fa

laila [671]

To solve this problem you must apply the proccedure shown below:

1. We know that 1 yard is 36 inches, therefore, 50 yards expressed in inches is:

$(50)(36)=1800in$

2. If he is 50 yards from school and the map shows that the school is 34 inches from his current location, when it shows 3 inches the real distance is:

$\frac{(1800in)(3in)}{34in}=158.82in$