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neonofarm [45]
1 year ago
10

Suppose you receive a postcard from a good friend with a picture of the Golden Gate Bridge in San Francisco. The postcard is 3.5

inches high and 5.5 inches wide. The fine print on the postcard states that the scale of the picture is 1:19,600. Based on the scale, what's the actual length of the Golden Gate Bridge?
Mathematics
1 answer:
Studentka2010 [4]1 year ago
8 0

Answer:

Actual length of the Bridge = 8983.33 feet.

Step-by-step explanation:

The scale is 1 unit = 19,600.

Height of the postcard is 3.5 inches.

So, original height of the bridge = 3.5 × 19,600 = 68,600 inches

= 5716.67 feet

Width of the postcard is 5.5 inches.

So, original width of the bridge = 5.5 × 19,600 = 107,800 inches

= 8983.33 feet


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What is the value of y in the following system y= 3x-5 6x+3y=15
Misha Larkins [42]
X=2. You use substitution to put the y=3x-5 into 6x+3y=15.
So you get 6x+3(3x-5)=15
=6x+9x-15=15
add 15 on both sides to get the x's alone and add the x's together.
6+9=15 -- 15+15=30
15x=30
30/15 =2
x=2
7 0
2 years ago
Read 2 more answers
Omar and Caleb each had a repair made on their cars. The initial cost of each repair is $1,000. Omar and
nataly862011 [7]

Answer:

Caleb paid less than Omar by $12.

Step-by-step explanation:

The initial cost of each repair is $1,000.

One  coupon is for $80 off the repair cost. The other coupon is for 15% off the repair cost.

Case 1:

Omar uses the $80 off the repair cost coupon first. He then uses the 15% off the repair cost coupon on  the remaining balance.

Step 1: 1000-80=920

Step 2: 920-(0.15\times920)=782 dollars

Case 2:

Caleb uses the 15% off the repair cost coupon first. He then uses the $80 off the repair cost coupon on  the remaining balance.

Step 1: 1000-(0.15\times1000)=850

Step 2: 850-80=770 dollars

Now, comparing the values we can see that Caleb paid less.

He paid less by 782-770=12 dollars.

8 0
2 years ago
The first term of a finite geometric series is 6 and the last term is 4374. The sum of all the term os 6558. find the common rat
Oliga [24]

A geometric series is written as ar^n, where a is the first term of the series and r is the common ratio.

In other words, to compute the next term in the series you have to multiply the previous one by r.

Since we know that the first time is 6 (but we don't know the common ratio), the first terms are

6, 6r, 6r^2, 6r^3, 6r^4, 6r^5, \ldots.

Let's use the other information, since the last term is 4374 > 6, we know that r>1, otherwise the terms would be bigger and bigger.

The information about the sum tells us that

\displaystyle \sum_{i=0}^n 6r^i = 6\sum_{i=0}^n r^i = 6558

We have a formula to compute the sum of the powers of a certain variable, namely

\displaystyle \sum_{i=0}^n r^i = \cfrac{r^{n+1}-1}{r-1}

So, the equation becomes

6\cfrac{r^{n+1}-1}{r-1} = 6558

The only integer solution to this expression is n=6, r=3.

If you want to check the result, we have

6+6*3+6*3^2+6*3^3+6*3^4+6*3^5+6*3^6 = 6558

and the last term is

6*3^6 = 4374

7 0
2 years ago
Suppose a company borrows 15,000 on 1/1/14 at 10% interest rate for a one year term. The company makes interest payments every q
goblinko [34]

Answer: 125

Step-by-step explanation:

Given that:

The principal = 15000

Rate = 10%

Years = 1 year = 12 month

Interest I = PRT/100

I = (15000 × 10 × 1)/100

I = 1500

The amount of interest expense that would they record in May will be

Interest = I/ 12 = 1500/12 = 125

5 0
2 years ago
While remodeling her kitchen Angela is repainting. She estimates that she paints 55 square feet every half-hour. How many square
madreJ [45]
110 square feet. 55x2=100
5 0
1 year ago
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