We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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Answer:
1000%
Step-by-step explanation:
c=10d,
3c will become 3*10d=30d
d is 10 times to c which converts to 1000%
Answer:
$6500
Step-by-step explanation:
Let the amount of money invested by Lian be $x
Interest rate = 5.2% per year
interest earned in first year will be 5.2% of amount of money invested by Lian .
(note: since in first year there will be no interest accrued on interest so interest for first year is simple interest )
interest earned in one year if money invested by Lian is $x
= 5.2% of $x (1)
But , it is given in one year she received interest of 338 dollars
so, 338 dollars must be equal to 5.2% of $x
equating $338 with 5.2% of $x , we have
5.2% of x = 338
=> (5.2/100) * x = 338
=>5.2 x = 338*100
=> x = 33800/5.2 = 6500.
Thus, amount of money Lian invested is $6500.
Given:
Cost of four lines = $125
Cost of each additional line = $15
Jason wants to spend at most $200 per month on cell phone expenses.
To find:
The inequality for the given situation.
Solution:
Let
be the number of additional line.
Cost of one additional line = $15
Cost of
additional line = 
Total cost = Fixed cost + Addition cost
= 
It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

Therefore, the correct option is C.
Let s and a represent the position of Sal and Amir respectively.
s=.75+4.5t and a=-.25+6.7t
When Sal catches Amir, s=a so we can say.
-.25+6.7t=.75+4.5t subtract 4.5t from both sides
-.25+2.2t=.75 add .25 to both sides
2.2t=1 divide both sides by 2.2
t=5/11 hours
t≈0.45 hours (to nearest hundredth of an hour)