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iragen [17]
2 years ago
8

Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe

e​ A, write an algebraic expression that represents the number of pounds of coffee B.
Mathematics
1 answer:
Svetach [21]2 years ago
5 0

Answer: 100-x

Therefore, the algebraic exp

Step-by-step explanation:

Given : x represents the number of pounds of coffee​ A.

The total weight of the mix of coffee A and coffee B = 100 pounds.

Then , we have the following expression to represents the number of pounds of coffee B:-

100-x

Therefore, the algebraic expression that represents the number of pounds of coffee B. :-

100-x

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What two products would you add to find 713​x48
umka21 [38]

9514 1404 393

Answer:

  40·713 and 8·713

Step-by-step explanation:

When this multiplication is carried out "by hand", the usual sum of partial products is ...

  8·713 + 40·713

5 0
1 year ago
Read 2 more answers
Drag each expression to show whether it is equivalent to (5⋅9x)+(5⋅1), 45x+15, or 15(3x−1).
JulijaS [17]

Part A: Option e: 5(9 x+1)

           Option f: 45 x+5

Part B: Option c: 15(3 x+1)

           Option d: (5 \cdot 9 x)+(5 \cdot 3)

Part C: Option a: (5 \cdot 9 x)-(5 \cdot 3)

           Option b: 45 x-15

Explanation:

Part A: The equation is (5 \cdot 9 x)+(5 \cdot 1)

Simplifying, we have,

45x+5

Taking the term 5 common out, we have,

5(9 x+1)

Thus, the above two expressions are equivalent to the equation (5 \cdot 9 x)+(5 \cdot 1).

Hence, Option e and Option f are the correct answers.

Part B: The equation is 45 x+15

Taking the term 15 common out, we have,

15(3 x+1)

Also, the equation can be rewritten as,

(5 \cdot 9 x)+(5 \cdot 3)

Thus, the above two expressions are equivalent to the equation 45 x+15

Hence, Option c and Option d are the correct answers.

Part C: The equation is 15(3 x-1)

Multiplying, we have,

45 x-15

The above expression can be rewritten as,

(5 \cdot 9 x)-(5 \cdot 3)

Thus, the above two expressions are equivalent to the equation 15(3 x-1)

Hence, Option a and Option b are the correct answers.

3 0
1 year ago
The students at Barton academy are planning a fundraiser to give money to an organization in their community. They voted for whi
Aneli [31]
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4 0
2 years ago
For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th
Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0
2 years ago
What is the constant of variation, k, of the direct variation, y = kx, through (5, 8)? k = – k equals negative StartFraction 8 O
Reil [10]

The value of constant of variation "k" is k = \frac{8}{5} \text{ or } 1.6

<em><u>Solution:</u></em>

Given that the direct variation is:

y = kx ----- eqn 1

Where "k" is the constant of variation

Given that the point is (5, 8)

<em><u>To find the value of "k" , substitute (x, y) = (5, 8) in eqn 1</u></em>

8 = k \times 5\\\\k = \frac{8}{5}\\\\k = 1.6

Thus the value of constant of variation "k" is k = \frac{8}{5} \text{ or } 1.6

3 0
2 years ago
Read 2 more answers
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