Consider the attached figure. All the triangles shown are similar, so
CB/CA = CD/CB
30/50 = projection/30
projection = 30^2/50
projection = 18
CB/CA = CD/CB
30/50 = projection/30
projection = 30^2/50
projection = 18
Nick is undertaking an expedition across the desert from A to B. In order to complete his journey he starts at A, walks 7km West
and then 24km North until he arrives at B. How much shorter would Nick's journey have been if he had gone by the shortest route across the desert?
1 answer:
Answer:
Shorting distance = 6 km
Step-by-step explanation:
Given:
Distance walk = 7 km west
Distance walk = 24 km north
Find:
Shorting distance
Computation:
Using Pythagorean theorem:
Magnitude AB = √AC² + BC²
Magnitude AB = √7² + 24²
Magnitude AB = √49 + 576
Magnitude AB = 25 Km
Total distance Nick walk = 7 km + 24 km
Total distance Nick walk = 31 km
Shorting distance = 31 km - 25 km
Shorting distance = 6 km
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Solution
Number of weeks in a year = 52 weeks
If in a normal year when each package of flea treatment lasts for 4 weeks, then in a year there Jim's dog will have to be treated for
Where as, when the fleas are bad in a year, the treatment lasts for only 3 weeks.
Then in a year Jim's dog would get
So Jim's dog will get 17- 13 =4 treatments more.
4 treatments that are made in 3 weeks each will be 4×3 =12 weeks more treatment