Nick is undertaking an expedition across the desert from A to B. In order to complete his journey he starts at A, walks 7km West
and then 24km North until he arrives at B. How much shorter would Nick's journey have been if he had gone by the shortest route across the desert?
1 answer:
Answer:
Shorting distance = 6 km
Step-by-step explanation:
Given:
Distance walk = 7 km west
Distance walk = 24 km north
Find:
Shorting distance
Computation:
Using Pythagorean theorem:
Magnitude AB = √AC² + BC²
Magnitude AB = √7² + 24²
Magnitude AB = √49 + 576
Magnitude AB = 25 Km
Total distance Nick walk = 7 km + 24 km
Total distance Nick walk = 31 km
Shorting distance = 31 km - 25 km
Shorting distance = 6 km
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Answer:
a) 20 ways
b) 10 ways
Step-by-step explanation:
When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.
Part a)
We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2
General formula of permutations of n objects taken r at time is:
Using the value of n=5 and r=2, we get:
Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.
Part b)
Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.
The general formula of combinations of n objects taken r at a time is:
Using the value of n=5 and r=2, we get:
Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice does not matters.
Answer:
0.632
Step-by-step explanation:
Given that a homeowner is three times as likely to purchase additional jewelry coverage as additional electronics coverage
If probability of purchasing additional electronics coverage = p, then prob of purchasing jewelry coverage = 3p
The two events are independent hence joint probability is product of these two.
i.e. P(both) =
This is given as 0.2
the probability that a homeowner purchases exactly one coverage.
= Prob he purchases I + prob he purchases II-2(prob he purchases both)