Question

There were 230{,}600230,600230, comma, 600 jobs available in the field of radiology in the year 201420142014. Each year, that number is expected to grow by 0.9\%0.9%0, point, 9, percent. Write a function that gives the expected number j(t)j(t)j, left parenthesis, t, right parenthesis of jobs in radiology ttt years from the year 201420142014. Do not use commas in your answer. J(t)=j(t)

Answer 1

Answer:

j(t)=230600(1.009)^t

Step-by-step explanation:

Increasing at a rate of 0.9\%0.9%0, point, 9, percent means the expected number of jobs keeps its 100\%100%100, percent and adds 0.9\%0.9%0, point, 9, percent more, for a total of 100.9\%100.9%100, point, 9, percent.

So each year, the expected number of jobs is multiplied by 100.9\%100.9%100, point, 9, percent, which is the same as a factor of 1.0091.0091, point, 009.

If we start with the initial number of jobs, 230{,}600230,600230, comma, 600 jobs, and keep multiplying by 1.0091.0091, point, 009, this function gives us expected number of jobs in radiology ttt years from 201420142014:

j(t)=230600(1.009)^t

Answer 2

Answer:

$J(t) =230600(1.009)^t$

Step-by-step explanation:

Given,

The initial number of jobs ( or jobs on 2014 ), P = 230,600

Also, the rate of increasing per year, r = 0.9% = 0.009,

Thus, the number of jobs after t years since 2014,

$J(t)=P(1+r)^t$

$=230600(1+0.009)^t$

$=230600(1.009)^t$

Which is the required function.