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FrozenT [24]
2 years ago
9

Jo is on the phone with a gardener who asks about the square feet of Jo's backyard. Jo counts 20 steps long and 40 steps wide (w

ith
each step being about 3 feet). About how many square feet is the backyard?
​
Mathematics
1 answer:
Sever21 [200]2 years ago
4 0

Hey there!

Each step is three feet. This can be represented by 3s= feet. We can plug that in to figure out our side lengths.

20(3)=60

40(3)=120

Now we can multiply these two together to get the area.

120(60)= 7,200

Therefore, his backyard is about 7,200 square feet.

I hope this helps!

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Show one way to count from $82 to $512
Sedaia [141]
<span><u><em>First way:</em></u>
The easiest and simplest way is to <u>count by 1</u> starting from 82 till you reach 512.
<u>This will go as follows:</u>
82, 83, 84, 85, ........... , 510, 511, 512

<u><em>Second way:</em></u>
We can note that the two given numbers are even numbers. This means that the two numbers are divisible by 2.
Therefore, we can <u>count by 2</u> starting from 82 till we reach 512.
<u>This will go as follows:</u>
82, 84, 86, 88, ................... , 508, 510, 512

<u><em>Third way:</em></u>
We can note that the units digit in both numbers is the same (the digit is 2). This means that we can count from 82 till 512 by <u>adding 10 each time</u>.
<u>This will go as follows:</u>
82, 92, 102, 112, ......................, 492, 502, 512

Hope this helps :)</span>
5 0
1 year ago
Katrina has the option of an 8-year non-subsidized student loan of $32,000 at an annual interest rate of 3.5% or an 8-year subsi
Fiesta28 [93]

Answer: katrina will pay less interest on the 8-year non subsidized student loan

The total interest paid on the non-subsidized loan is USD 8,959

The total interest paid on the subsidized loan is USD 11,520

Step-by-step explanation:

Subsidized loan at 4.5% for 8years will be 4.5/100 × 32000 x 1/12= USD120/month, USD 1440/year. For 8 years, USD11,520

For non subsidized student loan at 3.5% will be 3.5/100 x 32000x 1/12= USD 93.33/month, USD 1,119per year and USD 8,959 for 8 years

6 0
2 years ago
For the diagram below figure b is a reflection of y=2x of the line y =x
Scilla [17]
The equation of the line would be y = (1/2)x.

To find the equation of a line that is reflected through the line y = x, we just switch the x and y. Then, solve for y.

y = 2x
x = 2y
0.5x = y


5 0
2 years ago
What error did Leah make?
Evgen [1.6K]

Answer:

the lines arent parallel, so you cant use corresponding angles theorem

3 0
1 year ago
A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

l=65 ft

h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

V= 1,277.63\pi\ ft^{3}

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}

6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

7) <u>Find the number of lane miles that were covered with salt</u>

8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to 1,277.63\pi\ ft^{3}

1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

7 0
2 years ago
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