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2 years ago

Ahmed has five more CDs than one-half the number of CDs Julia has. In this situation, what does c+ 5 represent?

Mathematics

2 answers:

KonstantinChe [14]2 years ago

6 0

The c+5 should represent the five more cds that he has thats more than julias

Ierofanga [76]2 years ago

3 0

Answer with Explanation:

Let total number of CD's = x

Then, number of CD kept by Julia $=\frac{C}{2}$

Number of CD's Ahmed have $=\frac{C}{2}+5$

Expressing the statement in terms of equation

Total number of CD's= Number of CD's possessed by Julia +Number of CD's Ahmed have

$x= \frac{C}{2}+\frac{C}{2}+5\\\\x=C+5$

So, In this situation, C+ 5 represent, total number of CD's.

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Step-by-step explanation:

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Here 0.01 because it is 1 month tax.

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2 years ago

How many intersections are there of the graphs of the equations below? One-halfx + 5y = 6 3x + 30y = 36 none one two infinitely

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Answer:

infinitely many

Step-by-step explanation:

You have the system

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2 years ago

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Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 400 seconds a

garri49 [273]

Answer:

Step-by-step explanation:

In the normal distribution curve, the mean is in the middle and each line to the left and to the right of that mean represent 1- and 1+ the standard deviation. If our mean is 400, then 400 + 50 = 450; 450 + 50 = 500; 500 + 50 = 550. Going from the mean to the left, we subtract the standard deviation and 400 - 50 = 350; 350 - 50 = 300; 300 - 50 = 250. We are interested in the range that falls between 350 and 450 as a percentage. That range represents the two middle sections, each containing 34% of the data. So the total percentage of response times is 68%. We are looking then for 68% of the 144 emergency response times in town. .68(144) = 97.92 or 98 emergencies that have response times of between 350 and 450 seconds.

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2 years ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

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d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

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c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

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d) ON the same fashion we want to know the norm of the second derivative of $\gamma$ .

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