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The difference of finish times has a mean of
μ = 105 -98 = 7 . . . . minutes
and a variance of
σ² = 10² +15² = 325 . . . . minutes²
Using a probability calculator, we find the probability to be
p(-5 < x < 5) ≈ 0.2030
μ = 105 -98 = 7 . . . . minutes
and a variance of
σ² = 10² +15² = 325 . . . . minutes²
Using a probability calculator, we find the probability to be
p(-5 < x < 5) ≈ 0.2030
Answer:
kick 1 has travelled 15 + 15 = 30 yards before hitting the ground
so kick 2 travels 25 + 25 = 50 yards before hitting the ground
first kick reached 8 yards and 2nd kick reached 20 yards
Step-by-step explanation:
1st kick travelled 15 yards to reach maximum height of 8 yards
so, it has travelled 15 + 15 = 30 yards before hitting the ground
2nd kick is given by the equation
y (x) = -0.032x(x - 50)
we know that maximum height occurs is given as
and maximum height is
y = 20
so kick 2 travels 25 + 25 = 50 yards before hitting the ground
first kick reached 8 yards and 2nd kick reached 20 yards