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2 years ago

11. Susan was given the following number to convert to scientific notation: 12,050,000

Mathematics

1 answer:

pashok25 [27]2 years ago

5 0

Answer:

eliminated, the bedtime increases by one minute. ... Description: This activity requires students to tell time to the half-hour (e.g. 4:00, 5:30, 11:30).

Step-by-step explanation:

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Zachary’s final project for college course took a semester to write and had 95,234 words.zachary wrote 35,295 words the first mo

kap26 [50]

Answer:

40,999

Step-by-step explanation:

95,234-35,295= 59,939 and then 59,939-19,240= 40,999

5 0

2 years ago

Line segments XY and ZY are tangent to circle O. Circle O is shown. Triangle X Y Z has points X and Z on the circle. Lines X Y a

pickupchik [31]

Answer:

The correct option is;

An isosceles triangle

Step-by-step explanation:

The parameters given are;

Line segments XY and ZY are tangents to circle O.

ΔXYZ has points X and Z on the circle.

XY and ZY are tangents that intersect at point Y outside the circle'

Therefore, given the circle has center O, then;

OY ≅ OZ = Radius of circle with center O

∠OXY ≅ ∠OZY = 90° (The radius line from the circle center to the tangent point is perpendicular)

OY ≅ OY (Reflexive property)

ΔOYX and ΔOYZ are right triangles (Triangle with one angle = 90°

ΔOYX ≅ ΔOYZ (Hypotenuse Leg, HL, rule of congruency)

Therefore;

XY = ZY (Corresponding Parts of Congruent Triangles are Congruent CPCTC)

Triangle XYZ is an isosceles triangle (Triangle with two equal sides).

4 0

2 years ago

762,508 expanded form using exponents

r-ruslan [8.4K]

762,508 in expanded form using exponents is given as:

$7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0$

<h3><u>Solution:</u></h3>

Given that we have to write 762, 508 in expanded form using exponents

Expanded form or expanded notation is a way of writing numbers to see the math value of individual digits

<h3><u>Write 762508 in Expanded form</u></h3>

Let us first find the place value of digits

Place value can be defined as the value represented by a digit in a number on the basis of its position in the number.

Place value of 7 = 700000

In 762508, 7 is in hundred-thousands place

Place value of 6 = 60000

In 762508, 6 is in ten-thousands place.

Place value of 2 = 2000

In 762508, 2 is in thousands place

Place value of 5 = 500

In 762508, 5 is in hundreds place

Place value of 0 = 0 x 10 = 0

In 762508, 0 is in tens place

Place value of 8 = 8

In 762508, 8 is in ones place

Therefore, the expanded form is given as:

700,000 + 60,000 + 2,000 + 500 + 0 + 8

<u><em>Using exponents we can write as,</em></u>

$7 \times 10^5 + 6 \times 10^4 + 2 \times 10^3 + 5 \times 10^2 +0 \times 10^1 + 8 \times 10^0$

6 0

2 years ago

weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probabi

kenny6666 [7]

Answer:

0.34134

Step-by-step explanation:

In other to solve for this question, we would be using the z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = Standard deviation

We are told in the question to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

From tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134

7 0

2 years ago

A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th

solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

= $10,000

If fare increases by $ 1.00

New fare = $5 + $1

= $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

= (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0

2 years ago