Part A

In the diagram below what is the approximate length of the minor arc XY

GalinKa [24]

The answer is B.

The formula for arc length is s = r(theta) Theta must be in radians, so convert 40 degrees to radians, which is 2pi/9. Multiply 2pi/9 by the radius, 9, and then you'll get the answer. Hopes this helps!

3 0

2 years ago

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What is the relationship between two lines whose slopes are −8 and 1 8 ?

zavuch27 [327]

Answer:

They are perpendicular lines

Step-by-step explanation:

If one line has slope -8 and the other one has slope 1/8, they must be perpendicular to each other because the condition for perpendicular lines is that the slope of one must be the "opposite of the reciprocal of the slope of the original line."

the opposite of -8 is 8 , and the reciprocal of this is 1/8

5 0

2 years ago

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Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o

aliina [53]

Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)± $t_{n_1+n_2-2}$ * $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$

$t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71$

[(33.99-26.56) ± 1.654 *( $3.71*\sqrt{\frac{1}{135} +\frac{1}{42} }$ )]

[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

$t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06$

[(475.12-321.34) ± 2.485 *( $33.06*\sqrt{\frac{1}{12} +\frac{1}{15} }$ )]

[121.96; 185.60]

I hope this helps!

3 0

2 years ago

The graph shows the influence of the temperature T on the maximum sustainable swimming speed S of Coho salmon. (b) Estimate the

Alex17521 [72]

From the graph it appears that S′(5) 2 ≈ and S′(25) 2 ≈ − . The important thing is that they do have opposite signs. The first means that at about 5ºC the Coho gains about 2 cm/sec while at 25ºC it loses about 2 cm/sec in maximum sustainable speed.

3 0

2 years ago

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What is the factored form of the binomial expansion 125x^3 + 525x^2 + 735x + 343?

yarga [219]

Answer:

Step-by-step explanation:

1. regroup terms

$125x^3+343+525x^2+735x$