Points P, Q, and S are collinear. What is m∠SQR?
1 answer:
Answer:
m∠SQR = 74°
Step-by-step explanation:
Points P, Q and R are collinear.
Therefore, angles PQR and angle RQS are the linear pair of angles.
Since linear pair of angles are supplementary angles.
m∠PQR + m∠RQS = 180°
By substituting the measures of the given angles,
(3m + 1) + (2m + 4) = 180
5m + 5 = 180
5m = 180 - 5
5m = 175
m =
m = 35
Since, m∠SQR = (2m + 4)°
= (2×35) + 4
= 74°
Therefore, m∠SQR = 74° is the answer.
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The picture in the attached figure
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Area of circle=pi*r²
area of the shaded region=364*pi cm²
area of the shaded region=area of the outer circle -area of the<span> inside circle
</span>area of the outer circle=pi*[2x]²----> 4*x²*pi cm²
area of the inside circle=pi*6²------> 36*pi cm²
364*pi=4*x²*pi-36*pi------> 364=4*x²-36
4*x²=364+36-----> 4*x²=400
x²=400/4----> x²=100
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the answer is
x=10 cm
we know that
Area of circle=pi*r²
area of the shaded region=364*pi cm²
area of the shaded region=area of the outer circle -area of the<span> inside circle
</span>area of the outer circle=pi*[2x]²----> 4*x²*pi cm²
area of the inside circle=pi*6²------> 36*pi cm²
364*pi=4*x²*pi-36*pi------> 364=4*x²-36
4*x²=364+36-----> 4*x²=400
x²=400/4----> x²=100
x=10 cm
the answer is
x=10 cm
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Step-by-step explanation:
answers are in the attachment below
