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tigry1 [53]
2 years ago
15

If the size of the sample to be used in a particular test of attributes has not been determined by utilizing statistical concept

s, but the sample has been chosen in accordance with random selection procedures
A) No inferences can be drawn from the sample.
B) The auditor has committed a nonsampling error.
C) The auditor may or may not achieve the desired risk of assessing control risk too low.
D) The auditor will have to evaluate the results by reference to the principles of discovery sampling.
E) The auditor may or may not achieve the desired
Mathematics
1 answer:
EleoNora [17]2 years ago
5 0

Answer:

C) The auditor may or may not achieve the desired risk of assessing control risk too low.

Step-by-step explanation:

In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.

This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean

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Harry owns a factory that makes plastic toys. Each toy is tested. If the toy is perfect, it is put into a box. The boxes are the
vlada-n [284]

Answer:

approximately 14 each hour

Step-by-step explanation:

500/100 = 5 = 1% of 500

2% of 500 = 10

500 - 10 = 490

490/36 = 13.6 or about 14

multiply 14 by the number of hours each day and you'll get the final answer

5 0
2 years ago
Iesha’s quality-control manager told her she must have 97% of her clocks functioning properly. She found a report that said 6 ou
german

Answer:

  • Keisha’s experimental probability is 1/50.
  • When the inventory is 4000 clocks, the prediction is that 3920 clocks will work.
  • Keisha will have more than 97% of the products working.

Step-by-step explanation:

These are three prediction that Keisha can make based on the report that said 6 of 300 clocks tested weren't working.

Base on that information, Keisha can calculate an experimental probability, dividing <em>clocks that don't work properly </em>by <em>the total amount of clocks</em><em>:</em>

<em>P_{clocks} = \frac{6}{300}=\frac{1}{50} = 0.02 (or 2\%)</em>

Therefore, the probability of success is 100% - 2% = 98%.

This means that Keisha has a probability of having 98% of all clocks functioning properly. So, she can make the prediction:<em> from 4000 clocks, 3920 will work. </em>Also, she can predict that she will actually have more than 97% working, because the experimental probability is higher than that.

6 0
2 years ago
Read 2 more answers
A rectangle that is x feet wide is inscribed in a circle of radius 25 feet. Express the area of the rectangle as a function of x
Viefleur [7K]

Answer:

A(x)=x(\sqrt{2500-x^{2} } ) is the area expressed as function of x,

and x: >0, <50 is the domain of the function.

Step-by-step explanation:

Draw an appropriate figure and then express the area of the rectangle as a function of x.

We know that the diagonal of a rectangle inscribed in a circle, will be equal to the diameter of the circle. 50 feet

let w = the width of the rectangle

therefore

x^2 + w^2 = 50^2\\w^2 = 2500 - x^2\\w = \sqrt{2500-x^{2} }

recall

Area = x*w

replace w

A(x)=x(\sqrt{2500-x^{2} } ) is the area expressed as function of x

b)state the domain of the function

x: >0, <50

7 0
2 years ago
QUICK! 75 POINTS !!Select all that are part of the solution set of csc(x) &gt; 1 and over 0 ≤ x ≤ 2π.
Vladimir79 [104]

Answer:

\frac{\pi}{4}

\frac{5\pi}{6}

Step-by-step explanation:

The answer uses the unit circle and that sine and cosecant are reciprocals.

The first choice doesn't even fit the criteria that x is between 0 and 2\pi (inclusive of both endpoints) because of the x=\frac{-7\pi}{6}.

Let's check the second choice.

\csc(\frac{\pi}{4})=\frac{2}{\sqrt{2}} \text{ since } \sin(\frac{\pi}{4})=\frac{\sqrt{2}}{2}.

\csc(\frac{\pi}{4})>1 \text{ since } \frac{2}{\sqrt{2}}>1

\csc(\frac{\pi}{2})=1 \text{ since } \sin(\frac{\pi}{2})=1 which means \csc(\frac{\pi}{2})=1 which is not greater than 1.

So we can eliminate second choice.

Let's look at the third.

\csc(\frac{5\pi}{6})=2 \text{ since } \sin(\frac{5\pi}{6})=\frac{1}{2} which means \csc(\frac{5\pi}{6})>1.

\csc(\pi)  isn't defined because \sin(\pi)=0.

So we are eliminating 3rd choice now.

Let's look at the fourth choice.

\csc(\frac{7\pi}{6})=-2 \text{ since } \sin(\frac{7\pi}{6})=\frac{-1}{2} which means \csc(\frac{7\pi}{6}) and not greater than 1.

I was looking at the rows as if they were choices.

Let me break up my choices.

So we said x=-\frac{7\pi}{6} doesn't work because it is not included in the inequality 0\le x \le 2\pi.

How about x=0?  This leads to \csc(0) which doesn't exist because \sin(0)=0.

So neither of the first two choices on the first row.

Let's look at the second row again.

We said \frac{\pi}{4} worked but not \frac{\pi}{2}

Let's look at the choices on the third row.

We said \frac{5\pi}{6} worked but not x=\pi

Let's look at at the last choice.

We said it gave something less than 1 so this choice doesn't work.

6 0
2 years ago
Read 2 more answers
Each airline passenger and his or her luggage must be checked to determine whether he or she is carrying weapons on to the airpl
Dafna1 [17]

Answer:

a

P_k  = 0.83

b

 N_{\mu} \approx  4 \ passengers

c

T_{\lambda} =  0.5 \ minutes

Step-by-step explanation:

From the question we are told that

The average number of passengers that arrive per minute is \lambda = 10

The average number of check that can be carried out in one minute is \mu= 12

Generally the probability that a passenger will have to wait before being checked for weapons is mathematically represented as

        P_k  = \frac{\lambda }{ \mu }

=>    P_k  = \frac{10 }{ 12}

=>    P_k  = 0.83

Generally the number of passengers are waiting in line to enter the checkpoint is mathematically represented as

     N_{\mu} =  \frac{\lambda^2}{\mu (\mu -\lambda) }

=>  N_{\mu} =  \frac{10^2}{12 (12 -10) }

=>  N_{\mu} \approx  4 \ passengers

Generally the average time a passenger spend at the checkpoint is mathematically represented as

      T_{\lambda} = \frac{ \frac{\lambda}{(\mu - \lambda)} }{ \lambda}

=>   T_{\lambda} = \frac{ \frac{ 10}{(12 - 10)} }{10}

=>   T_{\lambda} =  0.5 \ minutes

5 0
1 year ago
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