Answer:
Number of rectangles could alex draw with an area of 11cm² = 1
Step-by-step explanation:
Minimum length in centimeter grid = 1 cm
Alex is drawing rectangles with different areas on a centimetre grid.He can draw 3 different rectangles with an area of 12cm²
That is
These are the 3 different rectangles with an area of 12cm².
Now we need to find how many rectangles could alex draw with an area of 11cm².
11 = 1 x 11
So only one factorization is possible.
Number of rectangles could alex draw with an area of 11cm² = 1
We can use the Pythagorean Trigonometric Identity which says:
Since we need to find sin(t), we have to solve for it:
Let's plug in the given cos(t) value:
And solve sin(t):
Simplify further:
And it all simplifies down to:
Since it's in the 4th quadrant, the sin(t) value is going to be negative. So, your final answer is:
Hope this helps!
The question is incorrect.
The correct question is:
Three TAs are grading a final exam.
There are a total of 60 exams to grade.
(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?
Answer: 60!/(25!20!15!)
Step-by-step explanation:
The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’
n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1
The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:
n!/p! q! r!
Therefore,
The answer is 60!/25!20!15!
Answer:
A) The mean of the chi-square distribution is 0
A) is not a property of chi square distribution.
Step-by-step explanation:
We have to find the properties of a chi square test.
A) False
The mean of a chi square distribution is equal to the degree of freedom.
B) True
The chi-square distribution is non symmetric.
C) True
The chi square value can be zero and positive.
It can never be negative because it is based on a sum of squared differences .
D) True
The chi-square distribution is different for each number of degrees of freedom.
When we are working with a single population variance, the degree of freedom is n - 1.
Answer:
(2, 11/2)
Step-by-step explanation:
This is a vertical parabola; we know that because x is squared here, while y is not. The standard equation of a vertical parabola with vertex (h,k) is
4p(y-k) = (x-h)^2, where p is the distance between the vertex and the focus. Comparing
4p(y-k) = (x-h)^2 to
10(y-3) = (x-2)^2, we see that 4p = 10. Therefore, p = 10/4 = 5/2, which is the vertical distance between the focus and the vertex.
Since the coordinates of the vertex are easily read from the given equation
(x-2)^2=10(y-3): (h,k) = (2, 3)
all we need to do is to add p (5/2) to the y-coordinate (3);
The focus is at (2, 3 + 5/2), or (2, 11/2).
