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kherson [118]
2 years ago
9

A printing company is considering buying a new printing press. It has quotes from two different companies. Company A offers a pr

ess for $9,500 plus $75 per month for a repair contract that covers unlimited repairs. Company B offers a press for $10,500 and charges $150 per repair.
The table gives the probabilities of the numbers of repairs to the printing press offered by company
b. Number of Repairs
0 1 2 3
Probability
0.32 0.29 0.25 0.14

which offer is more cost-effective?
Mathematics
1 answer:
Ostrovityanka [42]2 years ago
8 0
The complete problem wants to know the more cost-effective choice is the printing company replaces its press machine every four years. With this in mind, if they choose Company A, the total amount that needs to be paid to cover 12(4) = 48 months will be Company A = 9 500 + 48(750) = $13 100 As for Company B, the highest probability of not having any repairs over the four years is 0.32 while there's 0.14 chance that number of repairs will be 3 over the time the contract is applied. This means that the possible amounts to be paid to Company B are Company B = 10 500 + 0(150) = $10 500 Company B = 10 500 + 1(150) = $10 650 Company B = 10 500 + 2(150) = $10 800 Company B = 10 500 + 3(150) = $10 950 This shows that choosing the machine from Company B would be better. Hence, the answer is Company B<span>.</span>
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160 cups of milk

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2 years ago
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The average low temperature by month in Nashville is represented by the function
malfutka [58]

Answer:

<h2>33</h2>

Step-by-step explanation:

Given the average low temperature by month in Nashville is represented by the function  f(x)=-1.4x² + 19x +1.7, where x is the month, the average rate of change is expressed as d[f(x)]/dx = 2(1.4x) + 19

d[f(x)]/dx  = 2.8x + 19

Since the number of months between March and August is 5 months and x is in months, hence we will substitute x = 5 into the resulting function to get  the average rate of change from March to  August as shown;

d[f(x)]/dx  at x = 5

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4 0
2 years ago
Two armadillos and three aardvarks sat in a five-seat row at the Animal Auditorium. What is the probability that the two animals
Serhud [2]

Answer:

      \dfrac{1}{15}

Explanation:

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The number of different combinations in which<em> two of the three aardvarks </em>can sit at the ends of the row is P(3,2):

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Now calculate the total number of different ways in which the animals can sit. It is P(5,5):

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Thus, <em>the probability that the two animals on the ends of the row were both armadillos or both aardvarks</em> is equal to the number of favorable outputs divided by the total number of possible outputs:

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8 0
2 years ago
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Answer:

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=0

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8 0
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