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Nesterboy [21]
2 years ago
13

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

e is modeled using the equation h(t) = –16t2 + 48t + 190. Approximately when will the projectile hit the ground? 1.5 seconds 3.2 seconds 5.3 seconds 6.2 seconds
Mathematics
2 answers:
Solnce55 [7]2 years ago
6 0

Answer:

The answer is C

Step-by-step explanation:

Over [174]2 years ago
3 0

Hello! :)

—————— ☆ ☆———————————————————————————-

Answer:

5.3 seconds

Step-by-step explanation:

The answer is 5.3 seconds because

If you solve this equation than you will see how it is 5.3 seconds.

Equation: h (t) = -16t ^ 2 + 48t + 190

Also if you graph it, the answer will be 5.3 seconds

—————— ☆ ☆————————————————————————————

Hope this helps! :)

By: BrainlyMember ^-^

Good luck!

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Lets use the formula RWT=J to solve this, where,

  • R is the rate
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<em><u>"If it takes 10 seconds for 10 printers to print out 10 pages of paper"</u></em> - here -

W is 10 printers, T is 10 seconds,  and J is 10 pages. We can write:

R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1


<u><em>"how many seconds will it take 50 printers to print out 50 pages of paper"</em></u><em> - here we use R=0.1 (previously found) to figure out T.</em>

<em>RWT=J\\(0.1)(50)T=50\\5T=50\\T=\frac{50}{5}\\T=10</em>

So it will take 10 seconds for 50 printers to print 50 pages.


ANSWER: 10 seconds

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What is the GCF of the terms of the polynomial −16y4 + 12y2 – 4y?
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Answer:

The GCF is - 4y

Step-by-step explanation:

Given the polynomial expression −16y4 + 12y2 – 4y?

If we carefully traverse all the terms we can factor out 4y from all the terms

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Hence the greatest common factor GCF = - 4y

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Sarah can bicycle a loop around the north part of Lake Washington in 2 hours and 30 minutes. If she could increase her average s
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Answer:

The length of the loop is approximately 49.58 km.

Step-by-step explanation:

Given:

Time required to ride bicycle in loop = 2 hours and 30 mins

Now we know that;

60 mins = 1 hour

30 mins =0.5 hour

so 2 hour and 30 mins = 2+0.5 = 2.5\ hrs

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and let Total distance of the loop be 'd'

Now we know that;

Distance is given by speed multiplied by time.

framing in equation form we get;

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Now Given:

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framing in equation form we get;

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Now distance is same for both so we will calculate the speed by equating the equations.

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Now Speed = 19.83 km/hr

Length of the loop (d) = 19.83\times 2.5 = 49.58 \ km

Hence the length of the loop is approximately 49.58 km.

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