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ioda
2 years ago
6

What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

Mathematics
1 answer:
RideAnS [48]2 years ago
6 0

Answer:

Step-by-step explanation:

Three step process.

Step 1, convert Q, R, P, and S to coordinates measured from point P rather than from the origin by subtracting P from each point:

Q' = Q-P = (-3-(-3),2-(-3)) = (0,5)

R' = R-P = (1-(-3),2-(-3)) =(4,5)

P' = P-P = (-3-(-3),-3-(-3)) =(0,0)

S' = S-P = (1-(-3),-3-(-3)) = (4,0)

Step 2, Apply the dilation factor (0.5):

Q'' = (0.5)Q' = (0.5*0, 0.5*5) = (0,2.5)

R'' = (0.5)R' = _____

P''= (0.5)P' = _____

S''= (0.5)S' = _____

Step 3, Convert coordinates back to the origin (vice point P) by adding P to each point.  These are the dilated points.

Q''' = Q'' + P = (0+(-3),2.5+(-3)) = (-3, -0.5)

R''' = R'' + P = _____

P''' = P'' + P = _____

S''' = S'' + P = _____

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Answer:

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Step-by-step explanation:

At the end of year 14, the balance from the deposits of X can be found using the annuity due formula:

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where P is the periodic payment, n is the number of payments and compoundings per year, t is the number of years, and r is the annual interest rate.

  A = X(1.07)(1.07^14 -1)/0.07 ≈ 24.129022X

This accumulated amount continues to earn interest for the next 28 years, so will further be multiplied by 1.07^28. Then the final balance due to deposits of X will be ...

  Ax = (24.129022X)(1.07^28) = 160.429967X

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The same annuity due formula can be used for the deposits of Y for the last 10 years of the interval:

  Ay = Y(1.07)(1.07^10 -1)/.07 = 14.783599Y

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Now we can write the two equations in the two unknowns:

  Ax +Ay = 100,000

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From the latter, we have ...

  X = Y +100

So the first equation becomes ...

  160.429967(Y +100) +14.783599Y = 100000

  175.213566Y +16,043.00 = 100,000

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Y is 479.17

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2 years ago
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The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo
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Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

IQR=Q_3-Q_1=16-6.5=9.5

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

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2 years ago
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