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zimovet [89]
2 years ago
7

Which could be the graph of f(x) = |x - h| + k if h and k are both positive? On a coordinate plane, an absolute value graph has

a vertex at (2, 1). On a coordinate plane, an absolute value graph has a vertex at (1, negative 4). On a coordinate plane, an absolute value graph has a vertex at (negative 3, 2). On a coordinate plane, an absolute value graph has a vertex at (negative 4, negative 5).
Mathematics
1 answer:
Andrew [12]2 years ago
4 0

Answer:

Step-by-step explanation:

f(x) = |x - h| + k has a vertex at (h, k), where both h and k are positive.  Only

"On a coordinate plane, an absolute value graph has a vertex at (2, 1)"  satisfies those requirements.

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Define a function f on a set of real numbers as follows: f(x) = 3x − 1 x , for each real number x ≠ 0 Prove that f is one-to-one
dalvyx [7]

Answer with Step-by-step explanation:

We are given that

f(x)=\frac{3x-1}{x}

For each real number x\neq 0

To prove that f is one -to-one.

Proof:Let x_1 and x_2 be any nonzero real numbers such that

f(x_1)=f(x_2)

By using the definition of f to rewrite the left hand side of this equation

f(x_1)=\frac{3x_1-1}{x_1}

Then, by using the definition of f to rewrite the right hand side of this equation  of f(x_1)=f(x_2)

f(x_2)=\frac{3x_2-1}{x_2}

Equating the expression then we get

\frac{3x_1-1}{x_1}=\frac{3x_2-1}{x_2}

3x_1x_2-x_2=3x_2x_1-x_1

3x_1x_2-3x_1x_2+x_1=x_2

x_1=x_2

Therefore, f is one-to-one.

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2 years ago
Calculate the monthly payment for a 5-year car loan of $23,570 at 10.43% interest, compounded monthly. A. $247.44 b. $337.56 c.
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The answer is D on E2020!! I just took the test, you can trust this answer

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Answer: a + 4b -24

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Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of thre
Andreyy89

Answer:

The number of different combinations of three students that are possible is 35.

Step-by-step explanation:

Given that three out of seven students in the cafeteria line are chosen to answer a survey question.

The number of different combinations of three students that are possible is given as:

7C3 (read as 7 Combination 3)

xCy (x Combination y) is defines as

x!/(x-y)!y!

Where x! is read as x - factorial or factorial-x, and is defined as

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Now,

7C3 = 7!/(7 - 3)!3!

= 7!/4!3!

= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)

= (7×6×5)/(3×2×1)

= 7×5

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Therefore, the number of different combinations of three students that are possible is 35.

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Answer:

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