Answer: 
Step-by-step explanation:
In the simple radical form there are no square root is remain to find.
Since, the given expression,






Since, we do not need to find further square root of 7.
Thus, the required radical form of
is
.
Answer:
3d = 6
Step-by-step explanation:
since the distance is 6 feet, 3 times the distance (d) would give you the equation, 3d= 6.
:)
Answer:
She rode her bike 20 miles... I believe this may be a trick question.
Step-by-step explanation:
Let's break down this problem...
If she is going at a rate of 5 miles per hour while walking than the maximum she could have walked in 5 hours is 25 miles.
If Angela rode her bike for 20 miles, and the got off her bike and walked "<em>the rest of the way</em>" then she should have walked 50 miles. However as we already know her rate is 5 miles per hour while walking, and therefore could only have covered half that distance in 5 hours.
Is this a multiple choice question? Is there any misssing informaation?
Answer:
w = 4
YZ = 24
Step-by-step explanation:
Since, Y is a point lying between the points X and Z.
Therefore, relationship between the lengths of the segments will be,
length of segment XZ = length of XY + length of YZ
It's given in the question,
XZ = 12w - 8
YZ = 6w
XY = 4w
By substituting these values in the relation,
12w - 8 = 4w + 6w
12w - 8 = 10w
12w = 10w + 8
12w - 10w = 8
2w = 8
w = 4
Since, YZ = 6w
Therefore, YZ = 24
Answer:
The equation that Deon can use to find the time 't' it takes for his ride is t=distance/rate or t=15/20 or 0.75 hours.
Step-by-step explanation:
The relationship between distance, rate and time is a common formula represented by d=rt where 'd'=distance, 'r'=rate and 't'=time. Distance is typically calculated in miles, where rate is given in miles/hour and time is the hours. In this case, because we are looking for 't', we would simply plug in the values of distance and rate to get 20=15t. In order to solve for 't', we need to use inverse (opposite) operations, dividing both sides by 15 and getting 0.75 hours for 't'.