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AVprozaik [17]
2 years ago
9

Oscar needs to ship 14 rock cds, 12 classical cds, and 8 pop cds. he can only pack only one type of cd in each box and he must p

ack the same number of cds in each box. what is the greatest number of cds oscar can pack in each box?
Mathematics
2 answers:
tatyana61 [14]2 years ago
7 0
We need to find the biggest/highest number that can "go into" all of these numbers without a remainder.

That number is 2.

2 is a factor (a number that can "go into") of all of these numbers.
Artyom0805 [142]2 years ago
6 0

Answer:

2

Step-by-step explanation:

Oscar needs to pack only one type of cd in each box and he must pack the same number of cd's in each box.

To solve this problem we would need to find the greatest common factor of the numbers given; the numbers that we have are 14, 12, 8.

First we are going to find the factors of all these three numbers:

14 = 1 x 2 x 7

12 = 1 x 2 x 2 x 3

8 = 1 x 2 x 2 x 2

The common factors of these three numbers are bolded:

14 = 1 x 2 x 7

12 = 1 x 2 x 2 x 3

8 = 1 x 2 x 2 x 2

We can see that the common factors are 1 and 2. The biggest of them is 2.

Therefore, the greatest number of cd's Oscar can pack in each box is 2

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Step-by-step explanation:


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A number changes from 50 to 76. What type of percent change is this? Calculate the percent change.
Novosadov [1.4K]

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52%

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Which inequality is true if p= 3.4?
BigorU [14]

Answer:

None of the equations are true for p = 3.4

Step-by-step explanation:

In order for the inequality to be valid we need to apply the value for p and check wether or not it is true. We gonna do for each of the following:

A. 3p < 10.2

3*3.4 < 10.2

10.2 < 10.2

Not true, since the left side is equal to the right side and not less.

B. 13.6 < 3.9p

13.6 < 3.9*3.4

13.6 < 13.26

Not true since 13.6 is greater than 13.26

C. 5p > 17.1

5*3.4 > 17.1

17 > 17.1

Not true since 17 is less than 17.1

D. 8.5 > 2.5p

8.5 > 2.5*3.4

8.5 > 8.5

Not true since the left side is equal to the right side.

7 0
2 years ago
Most graduate business schools require applicants to take the gmat. scores on this test are approximately normally distributed w
Harman [31]
We are looking for the probability :
P(X > n)=0.05
Transform the law to standard normal like this:
P(\dfrac{X-545}{100}> \dfrac{n-545}{100})=0.05
The above formula is equivalent to this one:
P(\dfrac{X-545}{100}< \dfrac{n-545}{100})=0.95
From normal law table, we read the value of \dfrac{X-545}{100}.
\dfrac{X-545}{100}=1.7
Solving the above equation for the score n:
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5 0
2 years ago
Kayleigh babysat for 11 hours this week. That was 5 fewer than 2/3 as many hours as she babysat last week, h. Write an equation
lukranit [14]

Answer: The answer is \textup{x}=\dfrac{2}{3}\textup{h}-5.


Step-by-step explanation: Given that Kayleigh babysat for 11 hours the present week. Also, this was 5 less than two-third of the number of hours she babysat last week, which is represented by 'h'.

We are to write an equation to represent the number of hours she babysat each week.

So, for that, let 'x' be the number of hours she babysat this week. Then, according to the question, we can write

\textup{x}=\dfrac{2}{3}\textup{h}-5.

Also, it is given that

\textup{x}=11.

Therefore,

11=\dfrac{2}{3}\textup{h}-5\\\\\Rightarrow \dfrac{2}{3}\textup{h}=16\\\\\Rightarrow \textup{h}=24.

Hence, using the above relation, we can find the number oh hours Keyleigh babysat each week.

Thus, the required equation is

\textup{x}=\dfrac{2}{3}\textup{h}-5,

where, 'x' and 'h' are the number of hours she sat this week and last week respectively.

 


4 0
2 years ago
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