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AVprozaik [17]
2 years ago
9

Oscar needs to ship 14 rock cds, 12 classical cds, and 8 pop cds. he can only pack only one type of cd in each box and he must p

ack the same number of cds in each box. what is the greatest number of cds oscar can pack in each box?
Mathematics
2 answers:
tatyana61 [14]2 years ago
7 0
We need to find the biggest/highest number that can "go into" all of these numbers without a remainder.

That number is 2.

2 is a factor (a number that can "go into") of all of these numbers.
Artyom0805 [142]2 years ago
6 0

Answer:

2

Step-by-step explanation:

Oscar needs to pack only one type of cd in each box and he must pack the same number of cd's in each box.

To solve this problem we would need to find the greatest common factor of the numbers given; the numbers that we have are 14, 12, 8.

First we are going to find the factors of all these three numbers:

14 = 1 x 2 x 7

12 = 1 x 2 x 2 x 3

8 = 1 x 2 x 2 x 2

The common factors of these three numbers are bolded:

14 = 1 x 2 x 7

12 = 1 x 2 x 2 x 3

8 = 1 x 2 x 2 x 2

We can see that the common factors are 1 and 2. The biggest of them is 2.

Therefore, the greatest number of cd's Oscar can pack in each box is 2

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If t stands for the number of years since 2000 write an equation for the deer population p as a function of t
seraphim [82]

Answer:

The population of deer after t years is given as function of t is  p × (1+\dfrac{\textrm r}{100})^{\textrm t}  

Step-by-step explanation:

Given as :

The number of years = t

The population of deer = p

Let The population of deer after t years = P

Let The rate of increase in population = r %

So,

The population of deer after t years = Initial population of deer × (1+\dfrac{\textrm rate}{100})^{\textrm Time}

Or, P = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Hence The population of deer after t years is given as function of t is  p × (1+\dfrac{\textrm r}{100})^{\textrm t}    answer

3 0
2 years ago
What property is used in the second step of solving the inequality below?
dsp73

Answer:

Addition property

Step-by-step explanation:

Given the inequality:

5x - 9 < 91

The step to take here to move 9 to the other side, is to perform the addition property by adding 9 to both sides.

Thus,

5x - 9 + 9 < 91 + 9

5x < 100

The final step is to perform the division property by dividing both sides by 5, in order to solve for x.

5x/5 < 100/5

x < 20.

4 0
2 years ago
Read 2 more answers
A small business ships specialty homemade candies to anywhere in the world. Past records indicate that the weight of orders is n
FinnZ [79.3K]

Answer with Step-by-step explanation:

Since we have given

n = 16

a) Describe the sampling distribution for the sample mean.

The sampling distribution of the mean is the population's mean from where the items are sampled.

It would be \mu

b. What is the standard error?

s=\dfrac{\sigma}{\sqrt{n}}\\\\s=\dfrac{14}{\sqrt{16}}\\\\s=\dfrac{14}{4}\\\\s=3.5

c. For 90% confidence, what is the margin of error?

Degrees of freedom = v - 1= 16-1 = 15

Using t-table, 1.753 cuts 5% level of significance in each tail.

so, Margin of error would be

1.753\times 3.5\\\\=6.1355

d. Based on the sample results, create the 90% confidence interval and interpret.

So, 90% confidence interval would be

110+6.136\\\\=116.136\\\\and\\\\110-6.136\\\\=103.86

(103.86,116.136)

3 0
2 years ago
A company produces precision 1 meter (1000 mm) rulers. the actual distribution of lengths of the rulers produced by this company
pogonyaev

Let X be the length of rulers. X follows Normal distribution with mean μ and standard deviation σ = 0.02. A sample of size n=4 is drawn from population and sample mean m=1000. We have to find 90% confidence interval for population mean μ.

Here population standard deviation is given to us so we will use z confidence interval for mean. It is given as

(Sample mean - Margin of error , Sample mean + Margin of error)

Where margin of error for z confidence interval is

ME = σ \frac{z_{\alpha/2}}{\sqrt{n}}

Where σ = population standard deviation = 0.02

n= sample size =4

z_{\alpha/2} = Critical z score value for given confidence level

We have to find here 90% confidence interval so confidence level c= 0.9

α = 1 -c =1-0.9 = 0.1

z_{\alpha/2} = z_{0.1/2} = z_{0.05}

Here we have to find z score value such that area below it is -z is 0.05 and above z is 0.05

Using excel function to find z score value

=NORM.S.INV(0.05) = -1.645

For calculating confidence interval we consider positive z score value which is 1.645

So the margin of error is

ME = \frac{0.02 * 1.645}{\sqrt{4}}

ME = 0.01645

90% confidence interval for mean is

(Sample mean - ME, Sample mean+ME)

1000- 0.01645, 1000+0.01645

(1000.01645, 999.9836)

Rounding interval upto 3 decimal places

(1000.016, 999.984)

90% confidence interval for population mean is (1000.016, 999.984)

7 0
2 years ago
Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit
Effectus [21]
Work the information to set inequalities that represent each condition or restriction.

2) Name the variables. 

c: number of color copies
b: number of black-and-white copies

3) Model each restriction:

i) <span>It takes 3 minutes to print a color copy and 1 minute to print a black-and-white copy.
</span><span>
</span><span>3c + b
</span><span>
</span><span>
</span><span>ii) He needs to print at least 6 copies ⇒ c + b ≥ 6
</span><span>
</span><span>
</span><span>iv) And must have the copies completed in no more than 12 minutes ⇒</span>

3c + b ≤ 12
<span />

4) Additional restrictions are c ≥ 0, and b ≥ 0 (i.e. only positive values for the number of each kind of copies are acceptable)

5) This is how you graph that:

i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.

ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.

iii) since c ≥ 0 and b ≥ 0, the region is in the first quadrant.

iv) The final region is the intersection of the above mentioned shaded regions.

v) You can see such graph in the attached figure.

6 0
2 years ago
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