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Studentka2010 [4]
2 years ago
15

Jamie just bought two boxes.The first box is square with each side measuring 10 units and is 4 units high.The second box is rect

angular and has twice the volume of the square box.If the height of the second box is 5 units and width is 10 units what is the length of the second box
Mathematics
1 answer:
MakcuM [25]2 years ago
7 0
Step 1
find the volume of the square box
volume=area of the base*height
area of the base=10²-----> 100 units²
height=4 units
volume square box=100*4----> 400 units³

step 2
volume rectangular box=2*volume square box
volume rectangular box=2*400------> 800 units³

volume rectangular box=L*W*H
H=5 units
W=10 units
Volume=800 units³
800=L*10*5------> solve for L
L=800/(10*5)------> L=16 units

the answer is
the length of the rectangular box is 16 units

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Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general a
Makovka662 [10]
There was 3000 general admission tickets sold and 500 kid ticket sold.

How did I get this?

First, we need to see what information we have.
$2.50 = General admission tickets = (G)
 $0.50 = kids tickets =  (K)
There were 6x as many general admission tickets sold as kids. G = 6K

We need two equations:
G = 6K  
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.

2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis

15K + .50K = 7750
combine like terms

15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.

K = 7750/15.50
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So, 500 kid tickets were sold.

Plug K into our first equation (G = 6k)

G = 6*500
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So, 3000 general admission tickets were sold,

Let's check this:

$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)




4 0
1 year ago
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