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Eduardwww [97]
2 years ago
5

During a test period, an experimental group of 10 vehicles using an 85 percent ethanol-gasoline mixture showed mean CO2 emission

s of 240 pounds per 100 miles, with a standard deviation of 20 pounds. A control group of 14 vehicles using regular gasoline showed mean CO2 emissions of 252 pounds per 100 miles with a standard deviation of 15 pounds. A quick comparison of the sample variances suggests that the population variances are
Mathematics
1 answer:
PIT_PIT [208]2 years ago
7 0

Answer:

A quick comparison of the sample variances suggests that the population variances <u><em>are same or almost equal.</em></u>

Step-by-step explanation:

The populations from which two samples are drawn are normally distributed.

The  variable used to predict another variable is called an independent variable.

F- distribution is used for the test of  two sample hypotheses of variances.

If two populations have equal variances then the test Statistic is nearly equal to 1.

<em>t= s²₁/s²₂i</em>

<em />

As the variances are almost or nearly equal the test statistic would be almost equal to 1.

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Which relation is a function of x? {(1, 2), (7, 6), (3, 2), (1, 0), (5, 6)} A 2-column table with 4 rows. Column 1 is labeled x
inna [77]

Answer: The answer is D . The graph

Step-by-step explanation: It was the answer given on Edge.

5 0
2 years ago
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LIGHTING Kyle is buying strands of outdoor lights for his luau. The total cost of the strands can be modeled by the function f(c
blagie [28]

Answer:

Step-by-step explanation:

A. Function before discount:

f(c)= 8.97c

This means that cost per strand of outdoor light is $8.97 and c is number of strands of outdoor light bought. Therefore to model the function g(c) after he has received a $5 discount on his purchase(total purchase)

g(c)=8.97c-5

B. cost of 6 strands of light before discount

f(c)= 8.97×6= $53.82

cost of 6 strands of light after discount

f(c)=8.97×6-5= $48.82

5 0
1 year ago
A neighborhood is trying to set up school carpools, but they need to determine the number of students that need to travel to the
katrin [286]

Answer:

The correct option is 1.

Step-by-step explanation:

From the given histogram it is clear that

In age group 5-10, the number of students is 7.

In age group 11-13, the number of students is 5.

In age group 14-18, the number of students is 4.

It means age of 7 students lie in the interval 5-10, age of 5 students lie in the interval 11-13 and age of 4 students lie in the interval 14-18.

Total number of elements in the data set is 7+5+4=16

In option 3 and 4 number of elements is data set is less than 16. So, option 3 and 4 are incorrect.

In option 2 all the data set lie in the interval 5-10. So, option 2 is incorrect.

In option 1,

Class intervals      elements           frequency

5-10                    5,6,7,8,9,10,10           7

11-13                  11,11,12,12,13            5

14-18                    14,14,15,16              4

From the above table we can conclude that data set 1 represented in the given histogram.

Therefore the correct option is 1.

4 0
2 years ago
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What is 200 percent of (0.020(5/4) + 3 ((1/5) - (1/4)))
Inessa [10]

Answer:

0.1/4-3/20=1/40-6/40=-1/8 200% of this is -1/4

Step-by-step explanation:

4 0
2 years ago
All I need is this answer,please help!!
il63 [147K]
Hello there,

There is a total of 40 animals in that in 10 zebras, 10 lions, 10 elephants, and 10 monkeys.
So the probability of them both being lions is pretty rare. 2/40 so that would give you a 1/20 chance of both crackers being both lions.

I hope this helps!
7 0
2 years ago
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