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Eduardwww [97]
2 years ago
5

During a test period, an experimental group of 10 vehicles using an 85 percent ethanol-gasoline mixture showed mean CO2 emission

s of 240 pounds per 100 miles, with a standard deviation of 20 pounds. A control group of 14 vehicles using regular gasoline showed mean CO2 emissions of 252 pounds per 100 miles with a standard deviation of 15 pounds. A quick comparison of the sample variances suggests that the population variances are
Mathematics
1 answer:
PIT_PIT [208]2 years ago
7 0

Answer:

A quick comparison of the sample variances suggests that the population variances <u><em>are same or almost equal.</em></u>

Step-by-step explanation:

The populations from which two samples are drawn are normally distributed.

The  variable used to predict another variable is called an independent variable.

F- distribution is used for the test of  two sample hypotheses of variances.

If two populations have equal variances then the test Statistic is nearly equal to 1.

<em>t= s²₁/s²₂i</em>

<em />

As the variances are almost or nearly equal the test statistic would be almost equal to 1.

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If KN =29, what is CN?
Nostrana [21]
29kn are equal to cn 2900000
Hope it was right.
6 0
2 years ago
QUESTION THREE (30 MARKS) 3.1 The mass of a standard loaf of white bread is, by law meant to be 700g with a population standard
kiruha [24]

Using the normal distribution and the central limit theorem, it is found that  there is a 0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

----------------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

----------------------------------

  • Mean of 700g means that \mu = 700
  • Standard deviation of 21g means that \sigma = 21
  • Sample of 64, thus n = 64
  • <u>For the sampling distribution of the sample mean</u>, the standard deviation is of s = \frac{21}{\sqrt{64}} = \frac{21}{8} = 2.625

The probability of finding a sample mean mass of 695g or below is the p-value of Z when X = 695, thus:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{695 - 700}{2.625}

Z = -1.905

Z = -1.905 has a p-value of 0.0284.

0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

A similar problem is given at brainly.com/question/22934264

7 0
2 years ago
1. If Ray ran 10.5 miles in 7 days, how many miles
Rama09 [41]
Jsjsjsjkssiisisisosisisisksk
8 0
1 year ago
Read 2 more answers
If the point (−5, −8) is reflected over the y-axis, what are the coordinates of the reflected point?
Komok [63]
I believe it would be (5,-8)
5 0
2 years ago
a scale drawing of a rectangular park is 5 inches wide and 7 inches long. the actual park is 280 yards long. whats the area of t
mars1129 [50]
7 inches → 280 yards
1 inch → 280 ÷ 7 = 40 yards
5 inches → 40 x 5 = 200 yards

Area = 280 x 200 = 56 000 yards

Answer: 56 000 yards
6 0
2 years ago
Read 2 more answers
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