Find the value of h for the parallelogram to the right.

If cos(t) = 2/7 and t is in the 4th quadrant, find sin(t).

Yuliya22 [10]

We can use the Pythagorean Trigonometric Identity which says:
$sin^2(t)+cos^2(t)=1$

Since we need to find sin(t), we have to solve for it:
$sin(t)= \sqrt{1-cos^2(t)}$

Let's plug in the given cos(t) value:
$sin(t) = \sqrt{1-cos^2( \frac{2}{7})}$

And solve sin(t):
$sin(t) = \sqrt{1- \frac{4}{49} } = \frac{x}{y} \sqrt{ \frac{49}{49}- \frac{4}{49} }$

Simplify further:
$sin(t) = \sqrt{ \frac{45}{49} } = \frac{ \sqrt{45} }{7} = \frac{ \sqrt{9*5} }{7}$

And it all simplifies down to:
$sin(t) = \frac{3 \sqrt{5} }{7}$

Since it's in the 4th quadrant, the sin(t) value is going to be negative. So, your final answer is:
$sin(t) = - \frac{ 3\sqrt{5} }{7}$

Hope this helps!

7 0

2 years ago

Explain why there are two sine ratios, two cosine ratios, and two tangent ratios for any right triangle

taurus [48]

Each angle has a sin, cos, and tan associated with it.
in a right angled triangle there are two other angles which each have ratios.

5 0

2 years ago

Read 2 more answers

Round to the nearest benchmark fraction 5/9

Stells [14]

1/2 because 5/9 is equivalent to 10/18. Half of 18 is 9 and 10 is close to 9 so the nearest benchmark fraction you should round to is 1/2. Hope this helps you!

5 0

2 years ago

Drag each expression to show whether it is equivalent to (5⋅9x)+(5⋅1), 45x+15, or 15(3x−1).

JulijaS [17]

Part A: Option e: $5(9 x+1)$