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2 years ago

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If the probability of a chance event is 0.82 it is more likely to happen then which of the following probabilities another chanc

e event 0.9, 1, 0.85,0.8

1 answer:

kati45 [8]2 years ago

7 0

Answer:

The event which holds a probability of 0.82 is more likely to happen than the event which has a probability of 0.8

Step-by-step explanation:

The probability for any event to happen goes from 0 to 1, 0 being that it won't happen no matter what and 1 being that it will always happen. In this range the higher the probability the more likely it is that this event will actually happen. With this in mind the only one of the options that is less likely to happen is the one with "0.8" chance to happen.

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By visual inspection determine the best-fitting regression model for the data plot below

Pie

Answer:

Exponential

Step-by-step explanation:

By visual inspection the graph generated by the points plotted is an exponential graph as the graph curves upward. The graph is also continous and differs from either a decreasing or increasing Linear graph, which shows a straight best of fit pattern. Hence, the graph most closely represents an exponential graph from visual examination.

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2 years ago

Read 2 more answers

What is the volume, in cubic in, of a cylinder with a height of 12in and a base radius of 6in, to the nearest tenths place?

Shtirlitz [24]

Answer:

1356.5 cubic inches

Step-by-step explanation:

Given information:

Height of the cylinder = 12 in.

Radius of base of the cylinder = 6 in.

We need to find volume of the cylinder.

Volume of cylinder:

$V=\pi r^2h$

where, r is the radius of base and h is height of the cylinder.

Substitute the given values in the above formula.

$V=\pi (6)^2(12)$

$V=(3.14)(36)(12)$ $[\because \pi=3.14]$

$V=1356.48$

Approx to nearest tenth.

$V\approx 1356.5$

Therefore, the volume of cylinder is 1356.5 cubic inches.

8 0

2 years ago

A $400,000 loan has monthly interest-only payments of $2,600. What is the annual interest rate? 6.5, 7.2, 7.4 or 7.8?

Amiraneli [1.4K]

(annual interest)/(loan amount) = interest rate
(12×$2,600)/$400,000 = .078 = 7.8% . . . . annual interest rate

6 0

2 years ago

Read 2 more answers

Javier is making a cake for a party. The recipe calls for 2 3 4 234 cups of flour, but he wants to triple the recipe. He guessed

GalinKa [24]

The correct question is
<span>Javier is making a cake for a party. The recipe calls for 2 3/4 cups of flour, but he wants to triple the recipe. He guessed and put in 7 cups of flour. How many more cups of flour should he have used?

we know that
2 3/4 cups of flour------> (2*4+3)/4----> 11/4 cups
if he </span>wants to triple the recipe------> 3*(11/4)----> 33/4 ----> 8 1/4 cups required

8 1/4-7=1 1/4 cups

the answer is
1 1/4 cups

5 0

2 years ago

Evaluate the line integral by the two following methods. xy dx + x2y3 dy C is counterclockwise around the triangle with vertices

nadezda [96]

Answer:

a)

$\frac{2}{3}$

b)

$\frac{2}{3}$

Step-by-step explanation:

a) The first part requires that we use line integral to evaluate directly.

The line integral is

$\int_C xydx + {x}^{2} {y}^{3} dy$

where C is counterclockwise around the triangle with vertices (0, 0), (1, 0), and (1, 2)

The boundary of integration is shown in the attachment.

Our first line integral is

$L_1 = \int_ {(0,0)}^{(1,0)} xydx + {x}^{2} {y}^{3} dy$

The equation of this line is y=0, x varies from 0 to 1.

When we substitute y=0 every becomes zero.

$\therefore \: L_1 =0$

Our second line integral is

$L_2 = \int_ {(1,0)}^{(1,2)} xydx + {x}^{2} {y}^{3} dy$

The equation of this line is:

$x = 0 \implies \: dx = 0$

y varies from 1 to 2.

We substitute the boundary and the values to get:

$L_2 = \int_ {1}^{2}1 \cdot y(0) + {1}^{2} \cdot \: {y}^{3} dy$

$L_2 = \int_ {1}^2 {y}^{3} dy = \frac{8}{3}$

The 3rd line integral is:

$L_3 = \int_ {(1,2)}^{(0,0)} xydx + {x}^{2} {y}^{3} dy$

The equation of this line is

$y = 2x \implies \: dy = 2dx$

x varies from 0 to 1.

We substitute to get:

$L_3 = \int_ {1}^{0} x \cdot \: 2xdx + {x}^{2} {(2x)}^{3}(2 dx)$

$L_3 = \int_ {1}^{0} 8 {x}^{5} + 2 {x}^{2} dx = - 2$

The value of the line integral is

$L = L_1 + L_2 + L_3$

$L = 0 + \frac{8}{3} + - 2 = \frac{2}{3}$

b) The second part requires the use of Green's Theorem to evaluate:

$\int_C xydx + {x}^{2} {y}^{3} dy$

Since C is a closed curve with counterclockwise orientation, we can apply the Green's Theorem.

This is given by:

$\int_C \: Pdx +Q \: dy = \int \int_ R \: Q_y - P_x \: dA$

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int \int_ R \: 3 {x}^{2} {y}^{2} - y \: dA$

We choose our region of integration parallel to the y-axis.

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int_ 0^{1} \int_ 0^{2x} \: 3 {x}^{2} {y}^{2} - y \: dydx$

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int_ 0^{1} \: {x}^{2} {y}^{3} - \frac{1}{2} {y}^{2} |_ 0^{2x} dx$

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int_ 0^{1} \: 8{x}^{5} - 2 {x}^{2} dx = \frac{2}{3}$

8 0

2 years ago