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Natali [406]
2 years ago
8

Historically, in the early to middle 1900’s, households that had a telephone in their home were considered to earn an above aver

age annual income.
In 1948, pollsters famously predicted that Dewey would beat Truman for the presidency because Dewey was ahead in telephone polls. What bias led them to make the wrong prediction?

A. They only called on Tuesdays.
B. Many people did not have telephones.
C. They worded the question to favor Dewey.
D. Truman supporters would hang up.
Mathematics
1 answer:
irinina [24]2 years ago
3 0
The correct option is B.
From the information given in the question, we can see that only the rich in the society had telephone in their homes during the time of the said presidential election. Thus, the presidential candidate that was ahead in telephone polls was actually getting in touch with the rich only; he was not getting through to the larger part of the society, who are poor. Since both the poor and  the rich are going to vote in the presidential election, it means that Dewey campaigned to only a subset of the society, that was why he was defeated during the election.  
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RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
2 years ago
Alicia drove 265 miles in 5 hours. What is the average rate that she traveled?
Bumek [7]
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53 miles per hour. 

*I hope this helped!
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Answer:

d

Step-by-step explanation:

when f(x)=5......It can also be

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every whole number over one...1(625x)=625x

also 125(1)=125 therefore (625/125)x=5x

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HELLO,

Your answer is 130-50=80
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