Strange problem...
Constraints are Y <= 40 bags and X=Y in quantity. Nothing else matters. That's a bad decision unless the chicken farmer lost a poker hand to store X.
Answer:
Store 3
Step-by-step explanation:
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Answer:
The numbers are 19 and 71.
Step-by-step explanation:
Let x and y represent the two numbers. Then x + y = 90.
Also, if we assume that the larger number is y, then y = 3x + 14.
We must solve this system of linear equations. Since we already have the result of solution for y (y = 3x + 14), let's use the substitution method to find the solution:
x + y = 90 becomes x + 3x + 14 = 90, or:
4x = 76. Thus, x = 76/4, or 19. If x = 19, then y = 3(19) + 14, or y = 71.
The numbers are 19 and 71.
Note that these add up to 90, as they must, and that 71 is 14 more than 3 times 19.
I found a similar problem with its corresponding figure. It shows a recycling bin whose length is 1/2 meters, width is 1/2 meters, and height is 1/2 meters.
Based on the measure, the bin is a cube. Its volume formula is s³.
V = (1/2 m)³
V = 1/2 m * 1/2 m * 1/2 m
V = 1/8 m³
V = 0.5 m * 0.5m * 0.5m = 0.125 m³
0.125m³ = 1/8 m³
The volume of the paper recycling bin is 1/8 m³ or 0.125m³
1/2 * 1/2 = 1/4 there is a 25% chance that they will both occur