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balandron [24]
2 years ago
9

Twenty-one boys and eight girls go on a camping trip. In how many ways can a group of six be selected to gather firewood, given

the following conditions?
(a) The group consists of two girls and four boys.


(b) The group contains at least two girls.
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
6 0
(a)  there are 8C2  = 28 ways of picking 2 girls from 8
And there are  21C4  =  5985 ways of picking 4 boys

Required number of ways for 2g / 4b  = 28 * 5985 =  167,580 

(b) at least 2 girls means  combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or 
6 girls.

2g/4b  = 167,580 ways
3g/3b =  8C3 * 21C3 =  56 * 1330 = 74,480
4g/2b =  8C4* 21C2  =   70 * 210 = 14,700 
5g 1b = 8C5* 21 =  56*21 = 1176
6 girls  = 8C6 = 28

adding these up we get the answer to (b) which is  257,964

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The accompanying data are lengths (inches) of bears. Find the percentile corresponding to 65.5 in.
Jlenok [28]

Complete question is missing, so i have attached it.

Answer:

Percentile is 74th percentile

Step-by-step explanation:

All the lengths given are;

Bear Lengths 36.5 37.5 39.5 40.5 41.5 42.5 43.0 46.0 46.5 46.5 48.5 48.5 48.5 49.5 51.5 52.5 53.0 53.0 54.5 56.8 57.5 58.5 58.5 58.5 59.0 60.5 60.5 61.0 61.0 61.5 62.0 62.5 63.5 63.5 63.5 64.0 64.0 64.5 64.5 65.5 66.5 67.0 67.5 69.0 69.5 70.5 72.0 72.5 72.5 72.5 72.5 73.0 76.0 77.5

The number of lengths (inches) of bears given are 54 in number.

We are looking for the percentile corresponding to 65.5 in.

Looking at the lengths given, since they are already arranged from smallest to highest, let's locate the position of 65.5 in.

The position of 65.5 in is the 40th among 54 lengths given.

If the percentile is P, then;

P% x 54 = 40

P = (40 × 100)/54

P ≈ 74

3 0
2 years ago
NEED HELP!!!! Based on this part of the soliloquy, which best describes Hamlet’s perception of life?
ANEK [815]
<span>He believes that life is full of pain and suffering.</span>
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Find the slope of the line on the graph write your answer as a fraction or a whole number not a mixed number or decimal.
Scorpion4ik [409]

Answer: 1

Step-by-step explanation:

Change in y/change in x

starting at y intercept. up 1 unit (change in y) and over 1 unit (change in x) to get to next point on line.

slope is 1/1 which reduces to 1.

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Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4
vekshin1

<u>Given:</u>

The given equation is \log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule \log _{c}(a)+\log _{c}(b)=\log _{c}(a b), we get;

\log _{4}(x(x-3))=\log _{4}(-7 x+21)

Again applying the log rule, if \log _{b}(f(x))=\log _{b}(g(x)) then f(x)=g(x)

Thus, we have;

x(x-3)=-7 x+21

Simplifying the equation, we get;

       x^2-3x=-7 x+21

       x^2+4x=21

x^2+4x-21=0

Factoring the equation, we get;

(x-3)(x+7)=0

Thus, the solutions are x=3, x=-7

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)

     \log _{4}(3)+\log _{4}(0)=\log _{4}(0)

Since, we know that \log _{a}(0) is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)

    \log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)

    \log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)

Simplifying, we get;

Undefined = \log _{4}(70)

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

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A daylily farm sells a portion of their daylilies and allows a portion to grow and divide. The recursive formula an=1.5(an-1)-10
zaharov [31]

Answer:

Hence, the number of daylilies in the first year were:

600

Step-by-step explanation:

It is given that:

the recursive formula a_n=1.5(a_{n-1})-100 represents the number of daylilies, a, after n years.

Also we are given that in the fifth year they have 2,225 daylilies.

i.e.

a_5=2225

Also,

a_5=1.5a_4-100

a_4=1.5a_3-100

This means that:

a_5=1.5(1.5a_3-100)-100\\\\a_5=(1.5)^2a_3-100\times (1.5)-100

Similarly,

a_3=1.5a_2-100

so,

a_5=(1.5)^2\times (1.5a_2-100)-100\times (1.5)-100\\\\a_5=(1.5)^3a_2-(1.5)^2\times 100-(1.5)\times 100-100

and so, putting a_2 in terms of a_1 we get:

a_5=(1.5)^4a_1-(1.5)^3\times 100-(1.5)^2\times 100-(1.5)\times 100-100

Now on putting the value of a_5 we find the value of a_1

2225-(1.5)^4a_1-337.5-225-150-100\\\\2225=5.0625a_1-812.5\\\\2225+812.5=5.0625a_1\\\\3037.5=5.0625a_1\\\\a_1=\dfrac{3037.5}{5.0625}\\\\a_1=600

Hence, the number of daylilies in the first year were:

600

4 0
2 years ago
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