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liq [111]
2 years ago
7

The value of which of these expressions is closest to e?

Mathematics
1 answer:
jeka57 [31]2 years ago
8 0

Answer:

b

Step-by-step explanation:

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Calculate the value of x to one decimal place. inches
kakasveta [241]

Use the law of cosines: c^2=a^2+b^2-2ab\cos C

We have:

c=x\\a=3in\\b=7in\\C=54^o

substitute:

\cos54^o\approx0.5878\\\\c^2=3^2+7^2-2\cdot3\cdot7\cdot0.5878\\\\c^2=9+49-24.6876\\\\c^2=33.3129\to c=\sqrt{33.3129}\\\\c\approx5.8

5 0
2 years ago
You sell instruments at a Caribbean music festival. You earn $326 by selling 12 sets of maracas, 6 sets of claves, and x x djemb
MissTica
326 = 12m + 6c + x = 18 rounded to 19
8 0
2 years ago
Ken grew 4/5 of an inch last year. sang grew3/8 of an inch . who grew more and by how much?
Licemer1 [7]
Sang grew more. and by 17/40 ( I could be wrong)
4 0
2 years ago
Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −
Korolek [52]

The vector field

\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k

has curl

\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath

Parameterize S by

\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k

where

\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}

with 0\le u\le3 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k

Then by Stokes' theorem we have

\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv

which has a value of 0, since each component integral is 0:

\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0

4 0
2 years ago
If 153=2(z+z)n153=2(z+z)n153, equals, 2, left parenthesis, z, plus, z, right parenthesis, n, then what is the value of 2n(2z)-19
Nostrana [21]
What you must do for this case is to rewrite the first expression to find its value.
 We have then:
 153 = 2 (z + z) n
 Rewriting:
 153 = 2n2z
 Then,
 2n (2z) -193
 Substituting
 153-193 = -40
 Answer:
 the value of 2n (2z) -193 is
 -40
8 0
2 years ago
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