The value of which of these expressions is closest to e?

The volumes of two similar figures are 343 mm3 and 512 mm3. If the surface area of the larger figure is 192 mm2, what is the sur

Kobotan [32]

In geometry, similar figures are those whose ratios of the corresponding sides are equal and the corresponding angles are congruent. In relation to the volume, we determine first the cube roots of the given and find the ratio as shown below.

s1 / s2 = cube root of (512/343)
= 8/7
The square of this ratio is the ratio of the areas of the figure. If we let x be the area of the smaller figure then,
(8/7)^2 = 192 mm²/ x
The value of x from the equation is 147 mm².

The area therefore of the smaller figure is 147 mm².

3 0

2 years ago

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A web-based company has a goal of processing 90 percent of its orders on the same day they are received. If 434 out of the next

Kamila [148]

Answer:

We conclude that a web-based company are not exceeding their goal of 90%.

Step-by-step explanation:

We are given that a web-based company has a goal of processing 90 percent of its orders on the same day they are received.

434 out of the next 471 orders are processed on the same day.

Let p = proportion of orders processing on the same day they are received.

SO, Null Hypothesis, $H_0$ : p $\leq$ 0.90 {means that they are not exceeding their goal of 90%}

Alternate Hypothesis, $H_0$ : p > 0.90 {means that they are exceeding their goal of 90%}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of orders that are processed on the same day = $\frac{434}{471}$ = 0.92

n = sample of orders = 471

So, the test statistics = $\frac{0.92-0.90}{\sqrt{\frac{0.92(1-0.92)}{471} } }$

= 1.599

The value of z test statistics is 1.599.

Now, at 0.025 significance level the z table gives critical value of 1.96 for right-tailed test.

Since our test statistic is less than the critical value of z as 1.599 < 1.96, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that a web-based company are not exceeding their goal of 90%.

8 0

1 year ago

Sue played four games of golf for these games her modal score was 98 and her mean score was 100 her range of score was 10 what w

earnstyle [38]

Answer : Remaining two observation becomes 97 and 107.

Explanation :

Since we have given that

Mean = 100

Modal value = 98

Range = 10

As we know that ,

Range = Highest-Lowest

Let highest observation be x

Let lowest observation be y

So equation becomes x-y=10 ----equation 1

So, observation becomes

x,98,98,y

Now, we use the formula of mean i.e.

Mean = $\frac{\text{Sum of observation}}{\text{N.of observaton}}$

So, mean = $\frac{x=98=98+y}{4}=400\\\frac{196+x+y}{4}=100\\x+y=400-196\\x-y=204$

So our 2nd equation becomes

x+y=204

On using elimination method of system of linear equation on these two equation we get,

x=97

and

$x+y=204\\y=204-x\\y=204-97\\y=107$

Hence , remaining two observation becomes 97 and 107.

8 0

1 year ago

PLZ HELP! Oliver is 8 feet above the surface of the water. There is a school of fish 10 feet below the surface. A ledge with som

qwelly [4]

Answer:

26 feet, Oliver will have to travel 26 feet deep.

Step-by-step explanation:

8 feet added to 18 feet will be your answer.

8 0

2 years ago

If terri were stretching 4 days per week, how many days per week would she need to stretch to increase her frequency variable? 1

Olin [163]

Answer:

3 days is the right answer!!!!! good luck

Step-by-step explanation:

4 0

1 year ago

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