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leonid [27]
2 years ago
13

The volumes of two similar figures are 343 mm3 and 512 mm3. If the surface area of the larger figure is 192 mm2, what is the sur

face area of the smaller figure?
Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
5 0

Answer:

the smaller figure is 147 mm².

Kobotan [32]2 years ago
3 0
In geometry, similar figures are those whose ratios of the  corresponding sides are equal and the corresponding  angles are congruent. In relation to the volume, we determine first the cube roots of the given and find the ratio as shown below.
 
                         s1 / s2 = cube root of (512/343)
                                    = 8/7
The square of this ratio is the ratio of the areas of the figure. If we let x be the area of the smaller figure then, 
                      (8/7)^2 = 192 mm²/ x
The value of x from the equation is 147 mm². 

The area therefore of the smaller figure is 147 mm².
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kap26 [50]

Given:

A quadratic function has a line of symmetry at x = –3.5 and a zero at –9.

To find:

The other zero.

Solution:

We know that, the line of symmetry divides the graph of quadratic function in two congruent parts. So, both zeroes are equidistant from the line of symmetry.

It means, line of symmetry passes through the mid point of both zeroes.

Let the other zero be x.

-3.5=\dfrac{(-9)+x}{2}

Multiply both sides by 2.

-7=-9+x

Add 9 on both sides.

-7+9=-9+x+9

2=x

Therefore, the other zero of the quadratic function is 2.

8 0
2 years ago
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. Scores o
otez555 [7]

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So X = 52, \mu = 70, \sigma = 11

Z = \frac{X - \mu}{\sigma}

Z = \frac{52 - 70}{11}

Z = -1.64

Steven:

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So X = 52, \mu = 64, \sigma = 6

Z = \frac{X - \mu}{\sigma}

Z = \frac{52 - 64}{6}

Z = -2

Due to the higher z-score, David has the higher standardized score

3 0
2 years ago
The graph of f(x) = StartRoot x EndRoot is reflected over the y-axis. Use the graphing calculator to graph this reflection. Whic
labwork [276]

Answer:

<em>(–81, 9), (–36, 6), (–1, 1) </em> are the correct three points.

Step-by-step explanation:

Given the function:

f(x) =\sqrt x

Please refer to the attached image.

The green line shows the graph of actual function.

It is reflected over y axis.

The reflected graph is shown in black color in attached image.

When reflected over y axis, the sign of variable x changes from Positive to Negative.

So, the resultant function becomes:

f(x)=\sqrt{-x}

i.e. we will have to give the values of x as negative now.

so, the options in which value of x is negative are the possible answers only.

The possible answers are:

(–81, 9), (–36, 6), (–1, 1) and

(–49, 7), (–18, 9), (–1, 1)

Now, we will check the square root function condition.

In the 2nd option, (–18, 9) does not satisfy the condition.

So, the correct answer is:

<em>(–81, 9), (–36, 6), (–1, 1)</em>

7 0
2 years ago
N ÷ 3 +n for n =6 can you guys help me
Ludmilka [50]

Answer:

8 is your answer

Step-by-step explanation:

First plug in 6

6÷3+6

Then divide 6/3 which is 2

so 2+6 is 8

8 0
2 years ago
Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
2 years ago
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