Question

Which products result in a difference of squares? Select three options. A. (x minus y)(y minus x) B. (6 minus y)(6 minus y) C. (3 + x z)(negative 3 + x z) D. (y squared minus x y)(y squared + x y) E. (64 y squared + x squared)(negative x squared + 64 y squared)

Answer 1

Answer:

Step-by-step explanation:

Hello, please consider the following.

A. (x minus y)(y minus x)

  $(x-y)(y-x)=-(x-y)(x-y)=-(x-y)^2$

   This is not a difference of squares.

B. (6 minus y)(6 minus y)

   $(6-y)(6-y)=(6-y)^2$

   This is not a difference of squares.

C. (3 + x z)(negative 3 + x z)

   This is a difference of squares.

   $\boxed{(3+xz)(-3+xz)=(xz+3)(xz-3)=(xz)^2-3^2}$

D. (y squared minus x y)(y squared + x y)

   This is a difference of squares.

   $\boxed{(y^2-xy)(y^2+xy)=(y^2)^2-(xy)^2}$

E. (64 y squared + x squared)(negative x squared + 64 y squared)

   This is a difference of squares.

   $\boxed{(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)=(64y^2)^2-(x^2)^2}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer 2

Answer:

C D E

Step-by-step explanation:

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