In a survey, 39% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result
1 answer:
Answer:
Step-by-step explanation:
Hypotheses:
(Left tailed test)
p = sample proportion
n = sample size = 200
Sample proportion = p = 73/200 = 0.365
Std error = 0.03404
p difference = 0.365-0.39 = 0.025
t = 0.025/se = 0.7344
df = 199
p value = 0.2317
Since p >0.05 accept null hypothesis
No,the veterinarian does not have a right to be skeptical because there is no statistical evidence to support his claim.
You might be interested in
Using the uniform distribution, it is found that:
A,B) 0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.
C) 20% of the time does Josh’s bag arrive in less than 22 minutes.
--------------------------
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
--------------------------
- In the graph, we have that the distribution is uniform between 20 and 30 minutes, thus
--------------------------
Itens a and b:
- Above 27 minutes, thus:
0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.
--------------------------
Item c:
- Less than 22 minutes, thus:
0.2*100 = 20%
20% of the time does Josh’s bag arrive in less than 22 minutes.
A similar problem is given at brainly.com/question/15855314