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kipiarov [429]
2 years ago
14

In a​ survey, 39​% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result

to be too​ high, so he randomly selected 200 pet owners and discovered that 73 of them spoke to their pet on the telephone. Does the veterinarian have a right to be​ skeptical? Use the alphaequals0.05 level of significance.
Mathematics
1 answer:
olganol [36]2 years ago
8 0

Answer:

Step-by-step explanation:

Hypotheses:

H_0: p=0.39\\H_a:p

(Left tailed test)

p = sample proportion

n = sample size = 200

Sample proportion = p = 73/200 = 0.365

Std error = 0.03404

p difference = 0.365-0.39 = 0.025

t = 0.025/se = 0.7344

df = 199

p value = 0.2317

Since p >0.05 accept null hypothesis

No,the veterinarian does not have a right to be​ skeptical because there is no statistical evidence to support his claim.

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7 0
2 years ago
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Find the volume of the wedge cut from the first octant by the cylinder z=12-3y^2 and the plane x+y=2.
LuckyWell [14K]

Answer:

The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2  

0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2  

V = ∫∫∫ dzdydx  

dz has changed from zero to 12−3y^2  

dy has changed from zero to 2-x  

dx has changed from zero to 2  

V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =  

24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20

Step-by-step explanation:

8 0
2 years ago
Sophia was selling tickets at the high school dance. At the end of the evening, she picked up the cash box and noticed a $5 bill
borishaifa [10]
The first thing we will do in this case is to define variables:
 x = number of individual tickets.
 y = number of tickets per couple.
 We have then that the system of equations that represents the problem is:
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 Solving the system we have:
 x = 32
 y = 18
 Substituting we have:
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Over which interval are the exponential and linear function approximately the same? from 0.25 to 0.5 from 0.5 to 0.75 from 0.75
ryzh [129]

Answer:

Answer is 0.25 to 0.5

Step-by-step explanation:

Let the linear function be y=x

and exponential function be y=e^x

x          0.25   0.5    0.75    1.0     1.25    1.5

y          0.25   0.5    0.75    1.0     1.25    1.5

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Hence 0.36 to be nearer to 0.25, than other intervals

So answer is 0.25 to 0.5

3 0
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