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rosijanka [135]
2 years ago
6

A person kicks a 4.0-kilogram door with a 48-newton force causing the door to accelerate at 12 meters per second 2 . What is the

magnitude of the force exerted by the door on the person? A. 48 N B. 24 N C. 12 N D. 4.0 N
Mathematics
1 answer:
Hoochie [10]2 years ago
4 0

Answer: A. 48N

Step-by-step explanation: from Newton's third law of motion which states that action and reaction are equal and opposite. So this means that a person will get back same magnitude of force which he or she has exerted

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PLEASEE HURRYY Which expression is equivalent to the complex number. 10+3i
irga5000 [103]

Answer:

(4+7i)-2i(2+3i) = 10+3i

Step-by-step explanation:

We need to find the expression that is equivalent to the complex number 10+3i.

Option 1. 2i(4-5i)+(1-7i)

=8i-10i²+1-7i

∵ i² = -1

=8i-10(-1)+1-7i

=8i+10+1-7i

=11+i (incorrect)

Option 2. (4+7i)-2i(2+3i)

=4+7i-4i-6i²

=4+7i-4i-6(-1)

=4+7i-4i+6

=10+3i (Correct)

Option 3. (-3+5i)-3i(4+5i)

= (-3+5i)-12i-15i²

= -3+5i-12i-15(-1)

= -3+5i-12i+15

=12-7i (incorrect)

Option 4. 3i(4+7i)+(11+2i)

= 12i+21i²+11+2i

=12i+21(-1)+11+2i

= 12i-21+11+2i

=14i-10 (incorrect)

Hence, the correct option is (B).

5 0
2 years ago
Read 2 more answers
Most graduate business schools require applicants to take the gmat. scores on this test are approximately normally distributed w
Harman [31]
We are looking for the probability :
P(X > n)=0.05
Transform the law to standard normal like this:
P(\dfrac{X-545}{100}> \dfrac{n-545}{100})=0.05
The above formula is equivalent to this one:
P(\dfrac{X-545}{100}< \dfrac{n-545}{100})=0.95
From normal law table, we read the value of \dfrac{X-545}{100}.
\dfrac{X-545}{100}=1.7
Solving the above equation for the score n:
X-545=170
X=715, it is the score we are looking for. 
5 0
2 years ago
A.You have deposited $400 in a simple interest savings account, which pays three percent interest annually. Find the amount of i
djverab [1.8K]

Answer:

0 years: $0

5 years: $460

10 years: $520

15 years: $580

20 years: $640

6 0
2 years ago
Däne has a stamp collection. in one boo he has 6 pages with 15 stamps on each page. in another book,he has 9 pages with 20 stamp
galben [10]
6x15= 90

9x20= 180


180+90= 270


270 - 25 = 245        dane has 245 stamps left
8 0
2 years ago
NEED HELP ON NUMBER 13 AND 14
Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds  is given by the solution of the equation

8=y^4 +2y^3 - 4y^2 -5y +14.

We graph this equation and find the solutions to be

y=1;   y=1.302;     y=-2;    y=-2.302.

Since only positive solutions for y are valid in the real world we take only those.

Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when p(t)

Or

t^3 -14t^2 +20t +120

We graph this inequality and find the solutions to be

t and 4.88

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years 4.88

5 0
2 years ago
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