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rosijanka [135]

2 years ago

6

A person kicks a 4.0-kilogram door with a 48-newton force causing the door to accelerate at 12 meters per second 2 . What is the

magnitude of the force exerted by the door on the person? A. 48 N B. 24 N C. 12 N D. 4.0 N

1 answer:

Hoochie [10]2 years ago

4 0

Answer: A. 48N

Step-by-step explanation: from Newton's third law of motion which states that action and reaction are equal and opposite. So this means that a person will get back same magnitude of force which he or she has exerted

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What is equivalent fractions's to 2/11

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An equivalent fraction to 2/11 would be 4/22. You achieve this by multiplying both the numerator or denominator by the same number.

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The graph below represents the distance in miles (y), Jonathan travels on his bike in minutes (x). The table represents the dist

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Liam is constructing a square in which two of its vertices are points A and B. He has already used his straightedge and compass

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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

5 0

2 years ago

Read 2 more answers

Solve for<br> a. 7a-2b = 5a b

Nookie1986 [14]

For this case we have the following expression:

$7a-2b = 5ab$

From here, we must clear the value of a.

We then have the following steps:

Place the terms that depend on a on the same side of the equation:

$7a - 5ab = 2b$

Do common factor "a":

$a (7 - 5b) = 2b$

Clear the value of "a" by dividing the factor within the parenthesis:

$a =\frac{2b}{7-5b}$

Answer:

The clear expression for "a" is given by:

$a =\frac{2b}{7-5b}$

8 0

1 year ago

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